Gulp-sass 不会编译成 CSS

问题描述

我无法让 grunt-sass 编译为 .css.看过很多其他类似的帖子并使用了建议，但似乎没有任何效果.

I'm not able to get grunt-sass to compile to .css. Have seen a load of other similar posts and utilized suggestions but nothing seems to work.

我可以让其他插件正常工作(例如'del'删除内容，显示在这里)所以看起来我的环境没问题，我可以让普通的 vanilla sass 编译/监视正常工作.

I can get other plugins working fine (for example 'del' to delete stuff, shown here) so it seems my environment is ok, and i can get ordinary vanilla sass compile/watch to work fine.

这是我的设置以防万一:

Here's my setup just in case:

OSX Maverics 10.9.5

OSX Maverics 10.9.5

$ ruby -v
ruby 2.0.0p481 (2014-05-08 revision 45883) [universal.x86_64-darwin13]

$ sass -v
Sass 3.4.9 (Selective Steve)

$ npm -v
2.1.12

$ brew -v
Homebrew 0.9.5

项目目录结构如下:

    ├── index.html
    │
    ├── scss
    │    └── base.scss
    │          ├── _partial1.scss
    │          └── _partial2.scss
    │
    ├── assets
    │      └── css
    │           └── Nothing yet!
    │
    ├── deltest
    │    └── save.txt
    │
    ├── gulpfile.js
    │
    └── node_modules
         └── etc ...

这是我的 gulpfile.js:

Here's my gulpfile.js:

var gulp = require('gulp');
var sass = require('gulp-sass');
var del = require('del');

gulp.task('gsas', function() {
    gulp.src('./scss/base.scss')
        .pipe(sass({ includePaths : ['./scss/'] }))
        .pipe(gulp.dest('./assets/css'))
});

del(['!deltest/save.txt', 'deltest/delete.txt'], function (err, deletedFiles) {
    console.log('Files deleted:', deletedFiles.join(', '));
});

gulp.task('default', function() {
    console.log('AAAAAAAAAAAAAAAARGH!');
});

谁能看出这里出了什么问题?

Can anyone see what is wrong here?

已更新 - 相同的任务在 windows 框中静默失败:

这是来自 windows box 测试的 gulpfile.js，我什至没有 @importing 任何部分(目录结构 完全是，如任务设置中所示，我直接从实际中提取插件示例):

Here's the gulpfile.js from the windows box test and I'm not even @importing any partials (the dir structure is exactly as shown in the task setup, which i pulled straight from the actual plugin example):

var gulp = require('gulp');
var sass = require('gulp-sass');
var del = require('del');

gulp.task('sass', function () {
    gulp.src('./scss/*.scss')
        .pipe(sass())
        .pipe(gulp.dest('./css'));
});

del(['delete/delete.txt', '!delete/save.txt'], function (err, deletedFiles) {
    console.log('Files deleted:', deletedFiles.join(', '));
});

gulp.task('default', function () {
    console.log("Made it!");
});

在这个示例中，我再次让del"任务运行良好，但 gulp-sass 默默地失败了，这真的令人困惑.

In this example again I'm getting the 'del' task to run fine but gulp-sass fails silently and it's really baffling.

推荐答案

如果你希望 sass 任务在你从命令行运行 gulp 时执行，添加它作为 default 任务的依赖项:

If you want the sass task to execute when you run gulp from the command-line, add it as a dependency of the default task:

gulp.task('default', ['sass'], function() {
  //other stuff
});

这篇关于Gulp-sass 不会编译成 CSS的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！