本文介绍了将表单发布到弹出窗口而不是父窗口的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧! 问题描述 29岁程序员,3月因学历无情被辞! 我想发布一个forma poupup窗口。问题是,表单成功发布,但它也发布在父窗口上。我想在弹出窗口中提交formonly '< input type = button value =提交表单onclick =adNetworkForm ()> < script> 函数adNetworkForm(){ targetUrl =http://somesite.com var myForm = document.createElement('form'); myForm.method ='post'; //myForm.action = targetUrl; var inpt1 = document.createElement('input'); inpt1.setAttribute('name','a'); inpt1.setAttribute('type','hidden') inpt1.value =1; var inpt2 = document.createElement('input'); inpt2.setAttribute('name','b'); inpt2.setAttribute('type','hidden') inpt2.value = 2; myForm.appendChild(inpt1); myForm.appendChild(inpt2); document.body.appendChild(myForm); myForm.submit(popitup(targetUrl)); document.body.removeChild(myForm); } 函数popitup(url){ newwindow = window.open(url,'name','height = 600,width = 500'); if(window.focus){newwindow.focus()} return false; } < / script>' JS Fiddle p>您可以将一个onsubmit事件处理程序分配给窗体来调用一个函数,当窗体被提交时它会弹出一个新窗口并将窗体定位到该窗口中,如: < form action =...method =postonsubmit =some_popup_post(this);> <! - 表单字段等在这里 - > < / form> 而js代码是: function some_popup_post(form){ window.open('','formpopup','width = 400,height = 400,resizeable,scrollbars'); form.target ='formpopup'; } 你的意思是这样的.. I want to post a forma poupup window. Problem is, the form posts successfully but It also posts on the parent window. I want to submit the formonly in popup window '<input type= button value ="Submit Form" onclick="adNetworkForm()" ><script>function adNetworkForm(){targetUrl = "http://somesite.com" var myForm = document.createElement('form'); myForm.method = 'post'; //myForm.action = targetUrl; var inpt1 = document.createElement('input'); inpt1.setAttribute('name','a'); inpt1.setAttribute('type', 'hidden') inpt1.value = "1"; var inpt2 = document.createElement('input'); inpt2.setAttribute('name','b'); inpt2.setAttribute('type', 'hidden') inpt2.value = 2; myForm.appendChild(inpt1); myForm.appendChild(inpt2); document.body.appendChild(myForm); myForm.submit(popitup(targetUrl)); document.body.removeChild(myForm);} function popitup(url) {newwindow=window.open(url,'name','height=600,width=500');if (window.focus) {newwindow.focus()}return false;}</script>'JS Fiddle 解决方案 You could assign an onsubmit event handler to the form to call a function which pops open a new window when the form is submitted and targets the form to that window, like:<form action="..." method="post" onsubmit="some_popup_post(this);"><!-- form fields etc here --></form>And js code would be:function some_popup_post(form) { window.open('', 'formpopup', 'width=400,height=400,resizeable,scrollbars'); form.target = 'formpopup';}Do you mean something like this.. 这篇关于将表单发布到弹出窗口而不是父窗口的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持! 上岸,阿里云!