C++ Irrlicht 程序不链接:“对‘__imp_createDevice’的未定义引用"；

问题描述

我的 Irrlicht 程序没有链接.我使用的编译器是 g++.

My Irrlicht program doesn't link. The compiler I use is g++.

代码:

#include <irrlicht.h>

int main()
{
  irr::IrrlichtDevice *device = irr::createDevice();
  // And other init stuff
  while(device->run())
  {
    driver->beginScene();
    smgr->drawAll();
    guienv->drawAll();
    driver->endScene();
  }
  device->drop();
}

链接器输出:

...
(path)/main.cpp:28: undefined reference to `__imp_createDevice'
collect2.exe: error: ld returned 1 exit status

命令行:

g++.exe -o "(Path)Test.exe" "(Path)Testmain.o"
............MinGWliblibIrrlicht.a

链接器找到了库文件.怎么了?

The linker founds the library file. What's wrong?

我做了很少的实验.结果是，当我注释 createDevice() 行时，不会出现链接器错误.所以这意味着，该链接器找到了所有其他函数，即 IrrlichtDevice::run().

I made little experimenting. The result was, that when I comment createDevice()-line out, no linker errors will come. So that means, that linker founds all the other functions, i.e. IrrlichtDevice::run().

推荐答案

__imp_createDevice 指的是为动态链接到 .so 或 .dll 而构建的 .lib 文件.参见这篇文章和回答.

__imp_createDevice refers to a .lib file that is built for dynamic linking to an .so or .dll. See this post and answer.

查找为静态链接构建的 .lib，或者检查是否必须指定预编译器定义(例如 _IRR_STATIC_LIB_、IRRLICHT_STATIC 或 IRRLICHT_EXPORTS)以获得正确链接.

Find the .lib that is built for static linking, or alternatively check if you have to specify a pre-compiler definition such as _IRR_STATIC_LIB_, IRRLICHT_STATIC or IRRLICHT_EXPORTS to have correct linkage.

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