问题描述
我有一个 32 位进程,可以在 32 位或 64 位 Windows 中运行.因此,很自然地,如果进程试图访问文件 c:windowssystem32file.ext
,它会被重定向到 c:windowsSysWOW64file.ext
代码>.到目前为止一切顺利 - 我不想禁用重定向.
I have a 32-bit process that can run either in 32-bit or 64-bit Windows. So, naturally, if the process tried to access the file c:windowssystem32file.ext
, it would be redirected to c:windowsSysWOW64file.ext
. So far so good - I don't want to disable the redirection.
我的问题是我的进程实际上并没有访问文件 - 相反,它只是获取它的路径并将它写入一个文本文件,我想要那个文本文件在 64 位系统上读取 SysWOW64
,在 32 位系统上读取 system32
.我该怎么做?
My problem is that my process doesn't actually access the file - instead it just takes its path and writes it into a text file, and I want that text file to read SysWOW64
on a 64-bit system, and system32
on a 32-bit system. How can I do that?
推荐答案
以下代码将返回正确的系统目录(system32syswow64):
The following code will return the correct system directory (system32syswow64):
[DllImport("shell32.dll")]
public static extern bool SHGetSpecialFolderPath(
IntPtr hwndOwner, [Out]StringBuilder lpszPath, int nFolder, bool fCreate
);
public static string GetSystemDirectory()
{
StringBuilder path = new StringBuilder(260);
NativeMethods.SHGetSpecialFolderPath(IntPtr.Zero, path, 0x0029, false);
return path.ToString();
}
在 x86 上你会得到 %windir%System32在 X64 上你会得到 %windir%SysWow64
On x86 you'll get %windir%System32On X64 you'll get %windir%SysWow64
希望对你有帮助
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