SQLITE-删除第n行(Android)

问题描述

因此，我有一个ListView和一个DatabaseHandler，并且我想基于长按删除一个ListView项.也应该从数据库中删除它.

So I have a ListView and a DatabaseHandler, and I want to delete a ListView item based on a long click. It should be deleted from the database too.

但是当我删除I​​D为1的第一项时，ListView中的新第一项将是数据库中ID为2的项.

But when I delete the first item with ID 1, the new first item in the ListView will be the item with ID 2 in the DataBase.

ListView           Database
1                  1
2                  2
3                  3

删除后

ListView           Database
1                  2
2                  3

我想到了根据ListView ID删除数据库条目.

I thought of deleting the database entry according to the ListView ID.

delete from (select * from Student WHERE rownum = 2)

但这给我一个错误...

But it gives me an error...

我应该怎么做?谢谢！

推荐答案

您可以通过以下方法获得第(n + 1)条记录:

You can get the ( n+1 )th record by the following :

SELECT * FROM Students LIMIT 1 OFFSET n;

n是从零开始的索引.因此，您可以通过以下方式选择第二行:

n is the index you're after starting with zero. So you can select the 2nd row by:

SELECT * FROM Students LIMIT 1 OFFSET 1;

您还可以通过以下方式删除第二行:

You can also delete the second row by :

DELETE FROM Students WHERE id in (SELECT id FROM Students LIMIT 1 OFFSET 1)

这篇关于SQLITE-删除第n行(Android)的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！