问题描述
我有一个bash脚本,可以像这样调用期望脚本
I have a bash script that calls an expect script like so
$SCRIPTS_DIRECTORY/my_expect_script.sh $my_bash_array
看来,我可以将变量传递过来并使用它.对于此示例,变量似乎在[lindex $argv 0]
中.
I can pass a variable over, it seems, and use it.For this example the variable seems to be in [lindex $argv 0]
.
从bash开始,它将是一堆值,例如1 2 3 4 5
.
From bash, it will be a bunch of values, e.g. 1 2 3 4 5
.
我试图弄清楚如何使用Expect来获取这个变量,将其保存到一个数组中,然后遍历该数组以一次吐出多个命令.
I am trying to figure out how to use expect to grab this variable, save it to an array then loop through the array to spit out multiple commands one at a time.
所以我的输出应该是
send command 1 \r
send command 2 \r
等,直到到达数组末尾.
etc., until it reaches the end of the array.
我以为我希望将其分配为
I thought in expect I would assign it like
array set myArray [lindex $argv 0]
但是看起来我错了.
有人能在我看来有什么好地方可以解释从bash到更好的期望,或者知道如何做到这一点吗?我认为它相对简单,但是在某些方面对我的看法很渺茫.
Would anyone have any good places I can look that might explain going from bash to expect better, or know how to do this? I assume its relatively simple, but expect is very iffy with me in some aspects.
推荐答案
Sample.sh
my_array=(1 2 3 4 5)
expect sample.exp "${my_array[@]}"
Sample.exp
foreach arg $argv {
puts "arg : $arg"
}
输出:
dinesh@mypc:~$ ./sample.sh
arg : 1
arg : 2
arg : 3
arg : 4
arg : 5
dinesh@mypc:~$
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