将JSON反序列化为C#对象以将嵌套数组显示为网格中的字符串

问题描述

一切正常，然后反序列化确定.除了角色以外，其他信息都显示为System.Collections.Generic.List`1 [System.String]

Everything run and Deserialize OK. Except the Roles is show up as System.Collections.Generic.List`1[System.String]

问题

如果我想将每个字段附加到网格.有没有办法在不循环Roles属性的情况下将集合显示为字符串?

If I want to attach each field to a grid. Is there a way to show the collection as a string without looping through the Roles property?

JSON

[{
    "Name":"test",
    "Email": "[email protected]",
    "Roles": ["Admin","User","Guest"],
    "Age":"23"
},
{
  "Name":"test1",
  "Email": "[email protected]",
  "Roles": ["Admin", "User" ,"Guest"],
  "Age":"33"
}]

型号

public class example
{
    public string Name { get; set; }
    public string Email { get; set; }
    public IList<string> Roles { get; set; }
    public string Age { get; set; }
}

反序列化

List<Exampe> list = JsonConvert.DeserializeObject<List<Exampe>>(bundle);

推荐答案

如@Nkosi所述，这是一个XY问题.问题不在于反序列化，而是 DataGridView 如何处理复杂"属性类型.

As @Nkosi mentioned, this is a XY problem. The problem is not deserialization, but rather how DataGridView handles a "complex" property type.

您可以添加一个新属性以显示它:

You can add a new property to display it:

• 直接修改类定义即可:

• Either by directly modifying the class definition:

public class Example
{
    public string Name { get; set; }
    public string Email { get; set; }
    public string[] Roles { get; set; }
    public string Age { get; set; }

    public string RolesText => string.Join(", ", Roles ?? Array.Empty<string>());
}

或通过更改 DataGridView 的 DataSource :

dgv.DataSource = list.Select(x => new
{
    x.Name, x.Email, x.Age,
    Roles = string.Join(", ", x.Roles ?? Array.Empty<string>()),
}).ToList();

-

奖金:这是第二种方法的产生器:

Bonus: Here is an generator for the 2nd approach:

string GenerateModelFormatter<T>()
{
    return new StringBuilder()
        .AppendLine("x => new")
        .AppendLine("{")
        .AppendLine(string.Join(",\n", typeof(T).GetProperties()
            .Select(x => x.PropertyType != typeof(string[])
                ? $"\t{x.Name} = x.{x.Name}"
                : $"\t{x.Name} = string.Join(\", \", x.{x.Name} ?? Array.Empty<string>())")))
        .AppendLine("}")
        .ToString();
}

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