本文介绍了如何反序列化与破折号(“ - ”)的属性它的名字以NewtonSoft JsonConvert?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我们必须具有其名称中的破折号对象的一个JSON对象。例以下
We have a JSON object with one of the object having a dash in its name. Ex below.
{
"veg": [
{
"id": "3",
"name": "Vegetables",
"count": "25"
},
{
"id": "4",
"name": "Dal",
"count": "2"
},
{
"id": "5",
"name": "Rice",
"count": "8"
},
{
"id": "7",
"name": "Breads",
"count": "6"
},
{
"id": "9",
"name": "Meals",
"count": "3"
},
{
"id": "46",
"name": "Extras",
"count": "10"
}
],
"non-veg": [
{
"id": "25",
"name": "Starters",
"count": "9"
},
{
"id": "30",
"name": "Gravies",
"count": "13"
},
{
"id": "50",
"name": "Rice",
"count": "4"
}
]
}
我们如何反序列化此JSON?
How can we deserialize this json?
推荐答案
您可以通过实现这个DataContractJsonSerializer
You can achieve this by using DataContractJsonSerializer
[DataContract]
public class Item
{
[DataMember(Name = "id")]
public int Id { get; set; }
[DataMember(Name = "name")]
public string Name { get; set; }
[DataMember(Name = "count")]
public int Count { get; set; }
}
[DataContract]
public class ItemCollection
{
[DataMember(Name = "veg")]
public IEnumerable<Item> Vegetables { get; set; }
[DataMember(Name = "non-veg")]
public IEnumerable<Item> NonVegetables { get; set; }
}
现在你可以用这样的反序列化:
now you can deserialize it with something like this:
string data;
// fill the json in data variable
ItemCollection collection;
using (MemoryStream ms = new MemoryStream(Encoding.Unicode.GetBytes(data)))
{
DataContractJsonSerializer serializer = new DataContractJsonSerializer(typeof(ItemCollection));
collection = (ItemCollection)serializer.ReadObject(ms);
}
这篇关于如何反序列化与破折号(“ - ”)的属性它的名字以NewtonSoft JsonConvert?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!