UITextView中的超链接

问题描述

我正在尝试创建一个带有超链接的UITextView，这样当用户点击链接时，他们就会被带到safari来打开网页。我已阅读文本视图的链接检测器，但如果文本中存在实际网址（即www.google.com），这些示例始终显示链接检测有效。我希望它是常规文本，单击时会打开关联的URL。 （即Google就是文字，点击后会打开一个网址www.google.com）。如何在iOS7 / 8中完成此操作？

I am trying to create a UITextView with a hyperlink so that when the user clicks on the link, they are taken to safari to open the webpage. I have read on link detectors for a textview but those samples always show link detection working if an actual url is present in the text (ie. www.google.com). I want it to be regular text that, when clicked, opens an associated URL. (ie. Google is the text and when clicked, opens up a url www.google.com). How can I accomplish this in iOS7/8?

推荐答案

使用 NSAttributedString

NSAttributedString *attributedString = [[NSAttributedString alloc] initWithString:@"Google"
                                                                       attributes:@{ NSLinkAttributeName: [NSURL URLWithString:@"http://www.google.com"] }];
self.textView.attributedText = attributedString;

当然，您只需将文本的一部分设置为链接即可。请详细了解 NSAttributedString 。

Sure, you can set just a portion of the text to be the link. Please read more about the NSAttributedString here.

如果你想在打开链接之前有更多控制权并做一些事情。您可以将委托设置为 UITextView 。

If you want to have more control and do something before opening the link. You can set the delegate to the UITextView.

- (void)viewDidLoad {
    ...
    self.textView.delegate = self; // self must conform to UITextViewDelegate protocol
}

...

- (BOOL)textView:(UITextView *)textView shouldInteractWithURL:(NSURL *)URL inRange:(NSRange)characterRange {
    // Do whatever you want here
    NSLog(@"%@", URL); // URL is an instance of NSURL of the tapped link
    return YES; // Return NO if you don't want iOS to open the link
}

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