本文介绍了解析错误:语法错误,出现意外的T_ECHO的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
是什么原因导致此错误?
What is causing this error?
这是代码
<?php
session_start();
include("header.php");
if(!isset($_SESSION['uid'])) {
echo "You must be logged in to view this page";
}else{
?>
<center><h2>Battle Players</h2></center>
<br />
<table cellpadding="2" cellspacing="2">
<tr>
<td width="50px"><b>Rank</b></td>
<td width="150px"><b>Username</b></td>
<td width="200px"><b>Gold</b></td>
</tr>
<?php
$get_users = mysql_query("SELECT `id`,`overall` FROM `ranking` WHERE `overall`>'0' ORDER BY `overall` ASC") or die(mysql_error());
while($row = mysql_fetch_assoc($get_users)) { var_dump($row)
echo "<tr>";
echo "<td>". $row['overall']. "</td>";
$get_user = mysql_query("SELECT `username` FROM `user` WHERE `id`='".$row['id']."'") or die(mysql_error());
$rank_name = mysql_fetch_assoc($get_user);
echo "<td><a href=\"stats.php?id=" .$row['id']."\">" . $rank_name['username'] . "</a></td>";
$get_gold = mysql_query("SELECT `gold` FROM `stats` WHERE `id`='".$row['id']."'") or die(mysql_error());
$rank_gold = mysql_fetch_assoc($get_gold);
echo "<td>" . number_format($rank_gold['gold']) . "</td>";
echo "</tr>";
}
?>
</table>
<?php
}
include("footer.php");
?>
也在 http://pastebin.com/3nw310en
推荐答案
在var_dump($row)
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