本文介绍了Android的JSON结果处理的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有JSON结果是这样的:array.getJSONObject(J) -

I have Json result like this: array.getJSONObject(j) --

{执行code:WAT2,FreeIssue preFIX:结果
  \",\"DisPaySchedule$p$pfix\":\"\",\"NextFreeIssueNo\":\"1\",\"NextReturnNo\":\"20\",\"UploadedType\":\"1\",\"DisNextFreeIssueNo\":\"1\",\"DisNextFOCNo\":\"1\",\"NextVisitNo\":\"15\",\"DisNextOrderNo\":\"1\",\"UploadedOn\":\"Jun
  17 2011
  下午6点33分,NextReturnAcceptNo:1,BusinessUnit:HEMA,TXNReference preFIX:20110708
  ,订单preFIX:OR 4,UploadedMethod:3,FOC preFIX:搜索
  ,返回preFIX:RT4
  \",\"Retailer$p$pfix\":\"TEM4\",\"NextRetailerNo\":\"10\",\"NextInvoiceNo\":\"1\",\"NextGRNNo\":\"1\",\"Invoice$p$pfix\":\"IN4
  ,NextTXNReference:2,NextOrderNo:37,ReturnAccept preFIX:搜索
  \",\"PaySchedule$p$pfix\":\"PS4\",\"NextReceiptNo\":\"1\",\"NextFOCNo\":\"20\",\"NextPayScheduleNo\":\"41\",\"NextGRONo\":\"1\",\"DisReturn$p$pfix\":\"
  ,DisReceipt preFIX:,DisNextReturnNo:1,病症preFIX:搜索
  ,DisNextReceiptNo:1,DisNextPayScheduleNo:1,NextActivityNo:1,DisInvoice preFIX:
  ,DisNextInvoiceNo:1,UploadedBy:WAT2,DisFreeIssue preFIX:搜索
  ,DisFOC preFIX:,收据preFIX:RP4}

和我有拿vaue&安培;命名列表中的

And I have take vaue & name in the list:

我已经这样写的:

try {
  // getSoapResponseTableDataJson(responsePrimitiveData,
  // null,tablesName.get(i));
  String result = responsePrimitiveData.toString();
  JSONObject jsonobject = new JSONObject(result);
  ArrayList<String> toFieldList = new ArrayList<String>();
  ArrayList<String> toFieldValList = new ArrayList<String>();
  JSONArray array = jsonobject.getJSONArray("Table1");
  int max = array.length();

  HashMap<String, String> applicationSettings = new HashMap<String, String>();
   for (int j = 0; j < max; j++) {
     System.out.println(" -- array.getJSONObject(j) -- "
        + array.getJSONObject(j));
     String value = array.getJSONObject(j).getString("value");
     String name = array.getJSONObject(j).getString("name");
     applicationSettings.put(name, value);
   }
  System.out.println(" ---- json --- "+ applicationSettings);
 } catch (JSONException e) {
  e.printStackTrace();
}

这是说:
  org.json.JSONException:对于价值不价值

什么名字&安培;值?

what is name & value?

其实我想拿到钥匙单独的列表和放大器;值对在单独的列表....
我想利用这样的
       名称,如: {执行code,FreeIssue preFIX,DisPaySchedule preFIX,......}
       像值: {WAT2,,测试,...}

Actually I want to get the Key separate list & value pair in separate list....I want to take like this name like : {ExecutiveCode,FreeIssuePrefix,DisPaySchedulePrefix,.....} value like : {WAT2, "","TEst",.....}

请帮我。

在此先感谢....

推荐答案

只是觉得......没有 {名:东西} 在你的JSON ...

just think ... there is no {"name": "something"} in your JSON ...

修改 ...我念错的JSONObject文档... ...有没有JSONObject.getNames()

EDIT ... i read wrong JSONObject documentation ... there is no JSONObject.getNames()

使用obj.names()

use obj.names()

JSONObject obj = array.getJSONObject(j);
JSONArray[] names = obj.names();

迭代名

String name = names.getString(i);
String value = obj.getString(name);
applicationSettings.put(name, value)

旧的答案是

使用:

JSONObject obj = array.getJSONObject(j);
String[] names = JSONObject.getNames(obj);

迭代名

value = obj.getString(names[i])

这篇关于Android的JSON结果处理的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

11-01 19:33