将文件读入多维数组

问题描述

我想从文件中读取一个数字网格（n * n），然后将它们复制到一个多维数组中，一次复制一个int。我有代码读取文件并打印出来，但不知道如何获取每个int。我认为我需要splitstring方法和一个空白的定界符才能使用每个字符，但是在此之后我不确定。我也想将空白字符更改为0，但这可以等待！

I want to read in a grid of numbers (n*n) from a file and copy them into a multidimensional array, one int at a time. I have the code to read in the file and print it out, but dont know how to take each int. I think i need to splitstring method and a blank delimiter "" in order to take every charcter, but after that im not sure. I would also like to change blank characters to 0, but that can wait!

这是我到目前为止所获得的，尽管它不起作用。

This is what i have got so far, although it doesnt work.

        while (count <81  && (s = br.readLine()) != null)
        {
        count++;

        String[] splitStr = s.split("");
        String first = splitStr[number];
        System.out.println(s);
        number++;

        }
    fr.close();
    }

示例文件如下（需要空格）：

A sample file is like this(the spaces are needed):

26     84
 897 426
  4   7
   492
4       5
   158
  6   5
 325 169
95     31

基本上我知道如何读取文件并打印出来，但是不知道如何从读取器中获取数据并将其放入多维数组中。

Basically i know how to read in the file and print it out, but dont know how to take the data from the reader and put it in a multidimensional array.

我刚刚尝试过这，但它说无法从String []转换为String

I have just tried this, but it says 'cannot covernt from String[] to String'

        while (count <81  && (s = br.readLine()) != null)
    {
    for (int i = 0; i<9; i++){
        for (int j = 0; j<9; j++)
            grid[i][j] = s.split("");

    }

推荐答案

基于您的文件，这就是我的处理方式：

Based on your file this is how I would do it:

Lint<int[]> ret = new ArrayList<int[]>();

Scanner fIn = new Scanner(new File("pathToFile"));
while (fIn.hasNextLine()) {
    // read a line, and turn it into the characters
    String[] oneLine = fIn.nextLine().split("");
    int[] intLine = new int[oneLine.length()];
    // we turn the characters into ints
    for(int i =0; i < intLine.length; i++){
        if (oneLine[i].trim().equals(""))
            intLine[i] = 0;
        else
            intLine[i] = Integer.parseInt(oneLine[i].trim());
    }
    // and then add the int[] to our output
    ret.add(intLine):
}

在此代码的结尾，您将具有 int [] 的列表放入 int [] [] 。

At the end of this code, you will have a list of int[] which can be easily turned into an int[][].

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