问题描述
我在JavaScript 2号，我想一下，。他们都是33bit长
I have 2 numbers in javascript that I want to bit and. They both are 33bit long
在C＃：
in C#:
((4294967296 & 4294967296 )==0) is false
但在javascript：
but in javascript:
((4294967296 & 4294967296 )==0) is true
4294967296是（（长）1） - =;＆LT; 32
4294967296 is ((long)1) << 32
据我了解，这是由于JavaScript的转换价值进行逐位运算时INT32的事实。
As I understand it, it is due to the fact that javascript converts values to int32 when performing bit wise operations.
我如何解决此问题？关于如何更换位和一组其它数学运算，使位不丢失任何建议？
How do I work around this?Any suggestions on how to replace bit and with a set of other math operations so that bits are not lost?
推荐答案
您可以每个瓦尔的分成2个32位值（如高字和低字），然后做两个对的位操作。
You could split each of the vars into 2 32-bit values (like a high word and low word), then do a bitwise operation on both pairs.
下面的脚本作为Windows的.js脚本运行。您可以为网络代替WScript.Echo（）与警告（）。
The script below runs as a Windows .js script. You can replace WScript.Echo() with alert() for Web.
var a = 4294967296;
var b = 4294967296;
var w = 4294967296; // 2^32
var aHI = a / w;
var aLO = a % w;
var bHI = b / w;
var bLO = b % w;
WScript.Echo((aHI & bHI) * w + (aLO & bLO));
这篇关于如何做到位与在JavaScript上，比32位长的变量？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！