本文介绍了在一个字节转换成两个ASCII十六进制字符(ASCII两个字节)的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我要两个ASCII字节转换成一个十六进制字节。
例如。

I want to convert two ASCII bytes to one hexadecimal byte.eg.

的0x30 0x43中= GT;的0x0C,0x34 =的0x46 GT&; 0x4F ...

的ASCII字节是 0 9 之间的字母A之间的数字。 ˚F(仅大写),所以之间的的0x30 ... 0x39 ×41 ... 0×46

The ASCII bytes are a number between 0 and 9 or a letter between A and F (upper case only), so between 0x30 ... 0x39 and 0x41 ... 0x46

我知道如何构建 0x4F 与数字 0x34 0×46: 0x4F = 0x34 *为0x10 + 0×46

I know how "to construct" 0x4F with the numbers 0x34 and 0x46 : 0x4F = 0x34 * 0x10 + 0x46

所以,其实我是一个ASCII字节十六进制值转换。

So, in fact, i would to convert one ASCII byte in hexadecimal value.

对于这一点,我可以建立和阵列分配的十六进制值到的ASCII字符:

For that, i can build and array to assign the hexadecimal value to the ASCII char :

0x30 => 0x00
0x31 => 0x01
...
0x46 => 0x0F

不过,也许有一个最«正确»的解决方案。

But, maybe it have a most « proper » solution.

该程序将在一个AVRμC运行,并编译 AVR-GCC ,所以 scanf()的 / 的printf()解决方案是不适合的。

The program will be run on an AVR µC and is compiled with avr-gcc, so scanf() / printf() solutions aren't suitable.

你有一个想法?
谢谢

Have you got an idea ?Thanks

推荐答案

我不能让你的例子意义,但如果你想转换包含十六进制ASCII字符到字节值的字符串(例如,因此字符串56 成为字节0x56,你可以使用这个(假定您的系统使用的是ASCII)

i can't make sense of your examples, but if you want to convert a string containing hexadecimal ascii characters to its byte value (e.g. so the string "56" becomes the byte 0x56, you can use this (which assumes your system is using ASCII)

uint8_t*
hex_decode(const char *in, size_t len,uint8_t *out)
{
        unsigned int i, t, hn, ln;

        for (t = 0,i = 0; i < len; i+=2,++t) {

                hn = in[i] > '9' ? in[i] - 'A' + 10 : in[i] - '0';
                ln = in[i+1] > '9' ? in[i+1] - 'A' + 10 : in[i+1] - '0';

                out[t] = (hn << 4 ) | ln;
        }

        return out;
}

您会使用它像如

char x[]="1234";
uint8_t res[2];
hex_decode(x,strlen(x),res);

和RES(其中必须至少在参数的长度的一半)现在包含2个字节0x12,0x34

And res (which must be at least half the length of the in parameter) now contains the 2 bytes 0x12,0x34

还要注意的是这个code需要十六进制字母AF是资本,AF不会做(和它不会做任何错误检查 - 所以你必须将它传递有效的东西)。

Note also that this code needs the hexadecimal letters A-F to be capital, a-f won't do (and it doesn't do any error checking - so you'll have to pass it valid stuff).

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07-16 15:38
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