问题描述
我无法从fetchAll获取我的数据以选择性地打印。
I'm having trouble getting my data from fetchAll to print selectively.
在正常的mysql中我这样做:
In normal mysql I do it this way:
$rs = mysql_query($sql);
while ($row = mysql_fetch_array($rs)){
$id = $row['id'];
$n = $row['n'];
$k = $row['k'];
}
在PDO中,我遇到了问题。我绑定了params,然后我将获取的数据保存到$ rs像上面,目的是循环通过它的方式相同。
In PDO, I'm having trouble. I bound the params, then I'm saving the fetched data into $rs like above, with the purpose of looping through it the same way..
$sth->execute();
$rs = $query->fetchAll();
现在是麻烦的部分。我做什么PDO明智的得到匹配上面的while循环?我知道我可以使用print_r()或dump_var,但这不是我想要的。我需要做我以前能够使用普通的mysql,比如根据需要单独抓取$ id,$ n,$ k。可能吗?
Now comes the trouble part. What do I do PDO-wise to get something matching the while loop above?! I know I can use print_r() or dump_var, but that's not what I want. I need to do what I used to be able to do with regular mysql, like grabbing $id, $n, $k individually as needed. Is it possible?
提前感谢..
推荐答案
应为
while ($row = $query->fetch(PDO::FETCH_ASSOC)) {
$id = $row['id'];
$n = $row['n'];
$k = $row['k'];
}
如果您坚持 fetchAll
,然后
$results = $query->fetchAll(PDO::FETCH_ASSOC);
foreach($results as $row) {
$id = $row['id'];
$n = $row['n'];
$k = $row['k'];
}
PDO :: FETCH_ASSOC
仅提取列名称并省略数字索引。
PDO::FETCH_ASSOC
fetches only column names and omits the numeric index.
这篇关于PDO循环通道和打印fetchAll的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!