本文介绍了如何在 ColdFusion 中对结构数组进行排序的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我在 ColdFusion 中有一个结构数组.我想根据结构中的一个属性对该数组进行排序.我怎样才能做到这一点?我找到了 StructSort 函数,但它需要一个结构并且我有一个数组.
I have an array of structs in ColdFusion. I'd like to sort this array based on one of the attributes in the structs. How can I achieve this? I've found the StructSort function, but it takes a structure and I have an array.
如果这在 ColdFusion 中是不可能的,那么在 Java 中是否有可能(可能使用 Arrays.sort(Object[], Comparator)
)?
If this is not possible purely in ColdFusion, is it possible in Java somehow (maybe using Arrays.sort(Object[], Comparator)
)?
推荐答案
像往常一样,CFLib.org 有你想要的.
As usual, CFLib.org has exactly what you want.
http://cflib.org/udf/ArrayOfStructsSort
/**
* Sorts an array of structures based on a key in the structures.
*
* @param aofS Array of structures.
* @param key Key to sort by.
* @param sortOrder Order to sort by, asc or desc.
* @param sortType Text, textnocase, or numeric.
* @param delim Delimiter used for temporary data storage. Must not exist in data. Defaults to a period.
* @return Returns a sorted array.
* @author Nathan Dintenfass (nathan@changemedia.com)
* @version 1, December 10, 2001
*/
function arrayOfStructsSort(aOfS,key){
//by default we'll use an ascending sort
var sortOrder = "asc";
//by default, we'll use a textnocase sort
var sortType = "textnocase";
//by default, use ascii character 30 as the delim
var delim = ".";
//make an array to hold the sort stuff
var sortArray = arraynew(1);
//make an array to return
var returnArray = arraynew(1);
//grab the number of elements in the array (used in the loops)
var count = arrayLen(aOfS);
//make a variable to use in the loop
var ii = 1;
//if there is a 3rd argument, set the sortOrder
if(arraylen(arguments) GT 2)
sortOrder = arguments[3];
//if there is a 4th argument, set the sortType
if(arraylen(arguments) GT 3)
sortType = arguments[4];
//if there is a 5th argument, set the delim
if(arraylen(arguments) GT 4)
delim = arguments[5];
//loop over the array of structs, building the sortArray
for(ii = 1; ii lte count; ii = ii + 1)
sortArray[ii] = aOfS[ii][key] & delim & ii;
//now sort the array
arraySort(sortArray,sortType,sortOrder);
//now build the return array
for(ii = 1; ii lte count; ii = ii + 1)
returnArray[ii] = aOfS[listLast(sortArray[ii],delim)];
//return the array
return returnArray;
}
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