如何使用Git进行子模块稀疏检出?

问题描述

关于稀疏签出的文章很多，所以也有疑问.不幸的是，我没有找到具体的例子.我想得到以下示例工作:

There are a lot of articles and SO questions about sparse-checkout. Unfortunately I did not find concrete examples. I would like to get this following example work:

cd ~
mkdir sub && cd $_
git init 
mkdir foo && touch $_/foo
mkdir bar && touch $_/bar
git add .
git commit -am "Initial commit"

创建一个项目

cd ~
mkdir project && cd $_
git init
git submodule add ../sub sub
git config -f .gitmodules submodule.sub.shallow true
git config -f .gitmodules submodule.sub.sparsecheckout true
echo foo/* > .git/modules/sub/info/sparse-checkout
git commit -am "Initial commit"
git submodule update
cd sub
git checkout .

至此，我希望sub文件夹仅包含foo/foo而不包含bar.不幸的是，它不起作用:

A this point I am expecting sub folder to only contain foo/foo not bar. Unfortunately it doesn't work:

$ ls
bar/ foo/

我如何使它工作?

推荐答案

git submodule add本身签出子模块.

对我来说成功的是:

git init
# I did not find a way to add submodule in 1 step without checking out
git clone --depth=1 --no-checkout ../sub sub
git submodule add ../sub sub
git submodule absorbgitdirs
# note there is no "submodule.sub.sparsecheckout" key
git -C sub config core.sparseCheckout true
# note quoted wildcards to avoid their expansion by shell
echo 'foo/*' >>.git/modules/sub/info/sparse-checkout
git submodule update --force --checkout sub

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