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问题描述
我有以下内容
str = '[5.955894, 45.817792], [10.49238, 45.817792], [10.49238, 47.808381], [5.955894, 47.808381]'
我想拆分它以便我有一个像
这样的字符串数组['[5.955894, 45.817792]', '[10.49238, 45.817792]', ...]
这样 [...] 对象是数组的元素.包含封闭的 [ 和 ] 很重要.我已经走了这么远:
re.split('\D,\s\D', str)
但这给了我:
['[5.955894, 45.817792', '10.49238, 45.817792', '10.49238, 47.808381', '5.955894, 47.808381']
不是我想要的.
解决方案
我更喜欢使用 re.findall
并指定我想要的,而不是试图描述分隔符对于 re.split
\[
匹配 [[^\]]*
匹配除 ] 以外的任何内容\]
匹配 ]
I have the following
str = '[5.955894, 45.817792], [10.49238, 45.817792], [10.49238, 47.808381], [5.955894, 47.808381]'
I want to split it so that I have an array of strings like
['[5.955894, 45.817792]', '[10.49238, 45.817792]', ...]
So that the [...] objects are elements of the array. It is important that the enclosing [ and ] are included. I've come so far:
re.split('\D,\s\D', str)
But that gives me:
['[5.955894, 45.817792', '10.49238, 45.817792', '10.49238, 47.808381', '5.955894, 47.808381]']
Not really what I want.
解决方案
I prefer to use re.findall
and specify what I want instead of trying to describe the delimiter for re.split
>>> s = '[5.955894, 45.817792], [10.49238, 45.817792], [10.49238, 47.808381], [5.955894, 47.808381]'
>>> re.findall(r"\[[^\]]*\]",s)
['[5.955894, 45.817792]', '[10.49238, 45.817792]', '[10.49238, 47.808381]', '[5.955894, 47.808381]']
\[
matches [[^\]]*
matches anything but ]\]
matches ]
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