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问题描述

在GAE文档中,它指出:

lockquote
因为每个get()或put()操作调用一个单独的远程
过程调用(RPC),在循环内发出很多这样的调用是一种
低效的方式来同时处理一组实体或键。

谁知道我的代码中有多少其他的低效率问题,所以我想尽量减少。目前,我确实有一个for循环,每个迭代都有一个单独的查询。假设我有一个用户,并且一个用户有朋友。我想获取用户的每个朋友的最新更新。因此,我拥有的是该用户朋友的数组:

 对于朋友中的friend_dic:
email = friend_dic [' email']
lastUpdated = friend_dic ['lastUpdated']
userKey = Key('User',email)
query = ndb.gql('SELECT * FROM StatusUpdates WHERE ANCESTOR IS:1 AND ()):
status = qit.next()
status_list.append(status.to_dict())
raise ndb.Return(status_list)

有没有一种更有效的方式来做到这一点,也许不知何故将所有这些批处理成一个单一的查询?

解决方案

尝试查看NDB地图功能:



示例(假设您将您的朋友关系保留在单独的模型中,对于此示例,我假定关系
pre $
$ b $ def $ callback(entity)
email = friend_dic ['email']
lastUpdated = friend_dic ['lastUpdated']
userKey = Key('User',email)
query = ndb.gql('SELECT * FROM StatusUpdates WHERE ANCESTOR IS: 1 AND modifiedDate> :2',userKey,lastUpdated)
status_updates = yield query.fetch_async()
raise ndb.Return(status_updates)
$ b qry = ndb.gql(SELECT * FROM Relationships WHERE friend_to = 1,user.key)
updates = yield qry.map_async(回调)
#updates现在是一个状态更新列表



更新:



更好地理解您的数据模型:

 查询= [] 
status_list = []
在朋友中为friend_dic:
email = friend_dic ['email']
lastUpdated = friend_dic ['lastUpdated']
userKey = Key('User',email)
queries.append(ndb.gql('SELECT * FROM StatusUpdates WHERE ANCESTOR IS:1 AND modifiedDate >:2',userKey,lastUpdated).fetch_async())

用于查询查询:
status = yield query
status_list.extend([x.to_dict() for x in status])

raise ndb.Return(status_list)


In the GAE documentation, it states:

Who knows how many other inefficiencies I have in my code, so I'd like to minimize as much as I can. Currently, I do have a for loop where each iteration has a separate query. Let's say I have a User, and a user has friends. I want to get the latest updates for every friend of the user. So what I have is an array of that user's friends:

for friend_dic in friends:
        email = friend_dic['email']
        lastUpdated = friend_dic['lastUpdated']
        userKey = Key('User', email)
        query = ndb.gql('SELECT * FROM StatusUpdates WHERE ANCESTOR IS :1 AND modifiedDate > :2', userKey, lastUpdated)
        qit = query.iter()
        while (yield qit.has_next_async()):
           status = qit.next()
           status_list.append(status.to_dict())
raise ndb.Return(status_list)

Is there a more efficient way to do this, maybe somehow batch all these into one single query?

解决方案

Try looking at NDB's map function: https://developers.google.com/appengine/docs/python/ndb/queryclass#Query_map_async

Example (assuming you keep your friend relationships in a separate model, for this example I assumed a Relationships model):

@ndb.tasklet
def callback(entity):
  email = friend_dic['email']
  lastUpdated = friend_dic['lastUpdated']
  userKey = Key('User', email)
  query = ndb.gql('SELECT * FROM StatusUpdates WHERE ANCESTOR IS :1 AND modifiedDate > :2', userKey, lastUpdated)
  status_updates = yield query.fetch_async()
  raise ndb.Return(status_updates)

qry = ndb.gql("SELECT * FROM Relationships WHERE friend_to = :1", user.key)
updates = yield qry.map_async(callback)
#updates will now be a list of status updates

Update:

With a better understanding of your data model:

queries = []
status_list = []
for friend_dic in friends:
  email = friend_dic['email']
  lastUpdated = friend_dic['lastUpdated']
  userKey = Key('User', email)
  queries.append(ndb.gql('SELECT * FROM StatusUpdates WHERE ANCESTOR IS :1 AND modifiedDate > :2', userKey, lastUpdated).fetch_async())

for query in queries:
  statuses = yield query
  status_list.extend([x.to_dict() for x in statuses])

raise ndb.Return(status_list)

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11-01 23:18