本文介绍了如何将随机数插入sql server表?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我想在我的专栏中插入所有唯一的随机数。以下查询我得到的是相同的数字。
I want to insert all unique random number into my column. With the below query all i am getting is same number.
INSERT INTO CurrentSessionVariableDetails
(SessionId, FirstName, LastName, AddedForId, AddedById, CompanyId, ConnectionString, DataForYear, RoleName, ManagerName, CompanyLogoPath, IncludeProfileRatings, IncludeCompetency, ManagerId, LabelForCompetency, IsPerformanceRatingWithValue, IncludeDualObjRatingRev, IncludeSignOff, IsCompetencyRatingWithValue, IncludeObjectiveRating, RecordCPD, IncludeCPDSignOff)
Select
(SELECT CAST(RAND() * 1000000 AS INT)) AS [RandomNumber],
e.FirstName
, e.LastName
, e.Id
, null as AddedById
, e.Company_Id
, 'tesstring' as ConnectionString
, m.DataForyear
, (Select Name
from Role as r with (nolock)
where r.Id=e.Role_Id
) as RoleName
, (Select emp.FirstName + ' ' + emp.LastName
from Employee as emp with (nolock)
where emp.Id=e.ManagerId) as ManagerName
, c.Logo_Path
, c.IncludeProfileRatings
, c.IncludeCompetency
, e.ManagerId
, c.labelforcompetency
, c.IsPerformanceRatingWithValue
, c.IncludeDualObjectiveRatingReview
, c.includeSignOff
, c.IsCompetencyRatingWithValue
, c.IncludeObjectiveRating
, e.RecordCPD
, c.IncludeCPDSignedOff
from Employee as e with (nolock)
inner join MidYearAppraisal as m with (nolock) on e.Id = m.MidYear_AddedFor_Id
inner join Company as c with (nolock) on c.Id=e.Company_Id
Where m.isPublished =1
推荐答案
NEWID()
的新函数可以使用,否则你可以把你的结果带到一个变量并循环它以使用RAND()函数返回随机数。希望这可以帮助。
问候,
Sujay C。
which can be used or else you can take your result to a variable and loop over it to return Random number using RAND() function. Hope this helps.
Regards,
Sujay C.
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