问题描述
如何比较两个表( Table1
和 Table2
)并找到所有新条目或 Table2
。
使用SQL Server我可以使用
从Table1中选择* b $ b除
外*从Table2中选择* b $ b
这里是我想要的样本
Table1
A | 1
B | 2
C | 3
表2
A | 1
B | 2
C | 2
D | 4
所以,如果我比较这两个表,我希望我的结果向我展示以下内容
C | 2
D | 4
我尝试了几条没有运气的陈述。
现在我有了您的实际样本数据集,我可以编写一个查询,查找一个表中没有的每个域另一张表:
有24,729,816行。 有24,732,640行。
让我们看看1025中不在1024中的所有内容:
SELECT a.domain
FROM [inbound-acolyte-377:demo.1025] a
LEFT OUTER JOIN EACH [inbound-acolyte -377:demo.1024] b
ON a.domain = b.domain
WHERE b.domain IS NULL
结果:39,629行。
(已过8.1秒,已处理2.04 GB)
How would I compare two tables (Table1
and Table2
) and find all the new entries or changes in Table2
.
Using SQL Server I can use
Select * from Table1
Except
Select * from Table2
Here a sample of what I want
Table1
A | 1
B | 2
C | 3
Table2
A | 1
B | 2
C | 2
D | 4
So, if I comparing the two tables I want my results to show me the following
C | 2
D | 4
I tried a few statements with no luck.
Now that I have your actual sample dataset, I can write a query that finds every domain in one table that is not on the other table:
https://bigquery.cloud.google.com/table/inbound-acolyte-377:demo.1024 has 24,729,816 rows. https://bigquery.cloud.google.com/table/inbound-acolyte-377:demo.1025 has 24,732,640 rows.
Let's look at everything in 1025 that is not in 1024:
SELECT a.domain
FROM [inbound-acolyte-377:demo.1025] a
LEFT OUTER JOIN EACH [inbound-acolyte-377:demo.1024] b
ON a.domain = b.domain
WHERE b.domain IS NULL
Result: 39,629 rows.(8.1s elapsed, 2.04 GB processed)
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