问题描述
在python中,我们可以简单地做一个Type 5 UUID:
In python, to make a Type 5 UUID we can simply do:
import uuid
print uuid.uuid5(uuid.NAMESPACE_URL, 'my string')
浏览 java.util的Java文档.UUID ,我看不到该怎么做.首先,没有提到类型5.他们确实有3型,但签名是:
Looking through the java documentation for java.util.UUID, I don't see how to do it. First off, type 5 isn't mentioned. They do have a Type 3, but the signature is:
nameUUIDFromBytes(byte[] name)
Static factory to retrieve a type 3 (name based) UUID based on the specified byte array.
我们如何在Java中创建Type 5 UUID?
推荐答案
您可以通过遵循 https:中提出的代码来自己实现它://stackoverflow.com/a/28776880/1452094 .但是,这确实需要一些摆弄,因为j.u.UUID构造函数要花很长时间.
You can implement it yourself by following the code proposed in https://stackoverflow.com/a/28776880/1452094.However this does require some fiddling since the j.u.UUID constructor takes longs.
从 Java 8
开始,标准库似乎不支持类型5.有支持它的UUID实现.
As of Java 8
the standard library does not seem to support type 5. But third party libraries like "Apache Commons Id" have UUID implementations that do support it.
这是一个功能齐全的实现:
Here is a fully functional implementation:
import java.nio.charset.Charset;
import java.security.MessageDigest;
import java.security.NoSuchAlgorithmException;
import java.util.Objects;
import java.util.UUID;
public class UUIDType5 {
private static final Charset UTF8 = Charset.forName("UTF-8");
public static final UUID NAMESPACE_DNS = UUID.fromString("6ba7b810-9dad-11d1-80b4-00c04fd430c8");
public static final UUID NAMESPACE_URL = UUID.fromString("6ba7b811-9dad-11d1-80b4-00c04fd430c8");
public static final UUID NAMESPACE_OID = UUID.fromString("6ba7b812-9dad-11d1-80b4-00c04fd430c8");
public static final UUID NAMESPACE_X500 = UUID.fromString("6ba7b814-9dad-11d1-80b4-00c04fd430c8");
public static UUID nameUUIDFromNamespaceAndString(UUID namespace, String name) {
return nameUUIDFromNamespaceAndBytes(namespace, Objects.requireNonNull(name, "name == null").getBytes(UTF8));
}
public static UUID nameUUIDFromNamespaceAndBytes(UUID namespace, byte[] name) {
MessageDigest md;
try {
md = MessageDigest.getInstance("SHA-1");
} catch (NoSuchAlgorithmException nsae) {
throw new InternalError("SHA-1 not supported");
}
md.update(toBytes(Objects.requireNonNull(namespace, "namespace is null")));
md.update(Objects.requireNonNull(name, "name is null"));
byte[] sha1Bytes = md.digest();
sha1Bytes[6] &= 0x0f; /* clear version */
sha1Bytes[6] |= 0x50; /* set to version 5 */
sha1Bytes[8] &= 0x3f; /* clear variant */
sha1Bytes[8] |= 0x80; /* set to IETF variant */
return fromBytes(sha1Bytes);
}
private static UUID fromBytes(byte[] data) {
// Based on the private UUID(bytes[]) constructor
long msb = 0;
long lsb = 0;
assert data.length >= 16;
for (int i = 0; i < 8; i++)
msb = (msb << 8) | (data[i] & 0xff);
for (int i = 8; i < 16; i++)
lsb = (lsb << 8) | (data[i] & 0xff);
return new UUID(msb, lsb);
}
private static byte[] toBytes(UUID uuid) {
// inverted logic of fromBytes()
byte[] out = new byte[16];
long msb = uuid.getMostSignificantBits();
long lsb = uuid.getLeastSignificantBits();
for (int i = 0; i < 8; i++)
out[i] = (byte) ((msb >> ((7 - i) * 8)) & 0xff);
for (int i = 8; i < 16; i++)
out[i] = (byte) ((lsb >> ((15 - i) * 8)) & 0xff);
return out;
}
}
为了验证它是否有效,我运行了以下代码:
To verify it works I ran the following code:
public static void main(String[] args) {
UUID test = UUIDType5.nameUUIDFromNamespaceAndString(NAMESPACE_URL, "google.com");
System.out.println(test);
System.out.println(test.version());
}
这创建了输出:
5
针对官方python实现进行了验证:
Verified against the official python implementation:
fedb2fa3-8f5c-5189-80e6-f563dd1cb8f9
fedb2fa3-8f5c-5189-80e6-f563dd1cb8f9
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