问题描述
我有一个安静的网络服务,回复是:
I have a restful web service, and the response is:
{
"cities": [{
"id": "1",
"name": "City 01",
"state": "A1"
}, {
"id": "2",
"name": "City 02",
"state": "A1"
}]
}
但我希望如此:
{
[{
"id": "1",
"name": "City 01",
"state": "A1"
}, {
"id": "2",
"name": "City 02",
"state": "A1"
}]
}
如何配置JAX-RS以仅使用JAX-RS功能而不使用根节点生成JSON,而不是实现特定功能?我的代码需要可以在任何appserver上移植。
How I can configure JAX-RS to produces JSON without root node using only JAX-RS feature, and not implementation specific feature? My code needs to be portable across any appserver.
推荐答案
我遇到了与Glassfish v3相同的问题。我发现这种行为取决于JAX-RS的实现,切换到Codehaus的Jackson JAX-RS实现为我解决了这个问题。
I had the same problem with Glassfish v3. I found this behavior depends on the JAX-RS implementation and switching to Codehaus' Jackson JAX-RS implementation solved the problem for me.
如果你也使用Glassfish ,然后你可以通过在战争中加入 org.codehaus.jackson.jaxrs
以及 WEB-INF / web.xml来解决问题
配置如下:
If you're using Glassfish as well, then you can solve the problem by adding org.codehaus.jackson.jaxrs
to your war as well as to the WEB-INF/web.xml
configuration as follows:
<!-- REST -->
<servlet>
<servlet-name>RESTful Services</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>com.sun.jersey.config.property.resourceConfigClass</param-name>
<param-value>com.sun.jersey.api.core.PackagesResourceConfig</param-value>
</init-param>
<init-param>
<param-name>com.sun.jersey.config.property.packages</param-name>
<param-value>you.service.packages;org.codehaus.jackson.jaxrs</param-value>
<!-- NOTE: The last element above, org.codehaus.jackson.jaxrs, replaces the default
JAX-RS processor with the Codehaus Jackson JAX-RS implementation. The default
JAX-RS processor returns top-level arrays encapsulated as child elements of a
single JSON object, whereas the Jackson JAX-RS implementation return an array.
-->
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>RESTful Services</servlet-name>
<url-pattern>/your/rest/path/*</url-pattern>
</servlet-mapping>
或者,您可以简单地拦截客户端中的响应:
Alternatively, you might be able to simply intercept the response in the client:
function consumesCity(json) {
...
}
替换
... consumesCity(json) ...
with
function preprocess(json) {
return json.city;
}
... consumesCity(preprocess(json)) ...
这篇关于JAX-RS - 没有根节点的JSON的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!