Java 等价于 Explode 和 Implode(PHP)

本文介绍了Java 等价于 Explode 和 Implode(PHP)的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

我是 Java 新手，但在 PHP 方面有很好的经验，正在寻找 Java 中爆炸和内爆(PHP 中可用)函数的完美替代品.

I am new in Java although had a good experience in PHP, and looking for perfect replacement for explode and implode (available in PHP) functions in Java.

我在谷歌上搜索了相同的内容，但对结果不满意.任何人对我的问题有好的解决方案将不胜感激.

I have Googled for the same but not satisfied with the results.Anyone has the good solution for my problem will be appreciated.

例如:

String s = "x,y,z";
//Here I need a function to divide the string into an array based on a character.
array a = javaExplode(',', s);  //What is javaExplode?
System.out.println(Arrays.toString(a));

所需的输出:

[x, y, z]

推荐答案

Javadoc for String 揭示了 String.split() 是您正在寻找的关于 explode 的内容.

The Javadoc for String reveals that String.split() is what you're looking for in regard to explode.

Java 不包括连接"等价物的内爆".您可能只想编写几行代码，而不是像其他答案所建议的那样为简单函数包含巨大的外部依赖项.有很多方法可以做到这一点；使用 StringBuilder 就是其中之一:

Java does not include a "implode" of "join" equivalent. Rather than including a giant external dependency for a simple function as the other answers suggest, you may just want to write a couple lines of code. There's a number of ways to accomplish that; using a StringBuilder is one:

String foo = "This,that,other";
String[] split = foo.split(",");
StringBuilder sb = new StringBuilder();
for (int i = 0; i < split.length; i++) {
    sb.append(split[i]);
    if (i != split.length - 1) {
        sb.append(" ");
    }
}
String joined = sb.toString();

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