本文介绍了缺少值组合的完整数据框的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一个包含两个因素(distance)和年份(years)的数据框.我想将每个因子的所有 years 值都补 0.

I have a dataframe with two factors (distance) and years (years). I would like to complete all years values for every factor by 0.

即从此:

    distance years area
1      NPR     3   10
2      NPR     4   20
3      NPR     7   30
4      100     1   40
5      100     5   50
6      100     6   60

得到这个:

   distance years area
1       NPR     1    0
2       NPR     2    0
3       NPR     3   10
4       NPR     4   20
5       NPR     5    0
6       NPR     6    0
7       NPR     7   30
8       100     1   40
9       100     2    0
10      100     3    0
11      100     4    0
12      100     5   50
13      100     6   60
14      100     7    0

我尝试应用 expand() 函数:

library(tidyr)
library(dplyr, warn.conflicts = FALSE)

expand(df, years = 1:7)

但这只会生成一列数据框,并不会扩展原始数据框:

but this just produces one column dataframe and does not expand the original one:

# A tibble: 7 x 1
  years
  <int>
1     1
2     2
3     3
4     4
5     5
6     6
7     7

expand.grid() 也不起作用:

require(utils)
expand.grid(df, years = 1:7)

Error in match.names(clabs, names(xi)) :
  names do not match previous names
In addition: Warning message:
In format.data.frame(x, digits = digits, na.encode = FALSE) :
  corrupt data frame: columns will be truncated or padded with NAs

是否有一种简单的方法来扩展我的数据框?以及如何基于distanceuniqueLoc这两个类来展开?

Is there a simple way to expand my dataframe? And how to expand it based on two categories: distance and uniqueLoc?

distance <- rep(c("NPR", "100"), each = 3)
years <-c(3,4,7, 1,5,6)
area <-seq(10,60,10)
uniqueLoc<-rep(c("a", "b"), 3)

df<-data.frame(uniqueLoc, distance, years, area)

> df
  uniqueLoc distance years area
1         a      NPR     3   10
2         b      NPR     4   20
3         a      NPR     7   30
4         b      100     1   40
5         a      100     5   50
6         b      100     6   60

推荐答案

你可以使用tidyr::complete函数:

complete(df, distance, years = full_seq(years, period = 1), fill = list(area = 0))

# A tibble: 14 x 3
   distance years  area
   <fct>    <dbl> <dbl>
 1 100         1.   40.
 2 100         2.    0.
 3 100         3.    0.
 4 100         4.    0.
 5 100         5.   50.
 6 100         6.   60.
 7 100         7.    0.
 8 NPR         1.    0.
 9 NPR         2.    0.
10 NPR         3.   10.
11 NPR         4.   20.
12 NPR         5.    0.
13 NPR         6.    0.
14 NPR         7.   30.

或更短:

complete(df, distance, years = 1:7, fill = list(area = 0))

这篇关于缺少值组合的完整数据框的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

07-22 12:22
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