问题描述
如何动态填充字符串数组？
我希望有一些显而易见的东西我在这里失踪
Option Strict On
dim s（）as string
dim sTmp as string =" test"
dim i as integer
s（i）= new string（test）
上面的行给出 - 错误隐式转换字符串为1-dim数组
char
看了一下stringbuilder并转换为contructor中的char数组，但
没有找到答案
我得到一个不同的错误：变量''test''没有声明。
你想把哪些值放在数组中？
-
Armin
如何报价以及原因：
我感到很遗憾，但我无法理解你想要什么。
。
-
Herfried K. Wagner [MVP]
< URL：http：//dotnet.mvps.org/>
这与你引用数组的事实有关/>
索引[ie-s（i）]并且还通过
隐式标注数组的大小，指定索引的值[即 - （测试）这是错误的，
by-by-by]
试试这个：
选项严格打开
Dim s（）As String
Dim sTmp As String =" test"
Dim i As Integer
s（i）=" test"
- 或 -
s（i）= sTmp
-----
作为旁注，如果你想创建一个数组，而不是直接将它标注为
，你可以说：
Dim s（）As String = {" One"，" Two"" Three" }
希望这有帮助
J.
-
电子邮件列出的地址不是我的真实地址。请不要发送
有效电子邮件到该地址。
How do I dynamically populate a string array?
I hope there is something obvious that I''m missing here
Option Strict On
dim s() as string
dim sTmp as string = "test"
dim i as integer
s(i)=new string(test)
Above line gives - error implicit conversion string to 1-dim array of
char
Looked at stringbuilder and coverting to char array in contructor but
did not find an answer
I get a different error: variable ''test'' not declared.
Which values do you want to put in the array?
--
Armin
How to quote and why:
http://www.plig.net/nnq/nquote.html
http://www.netmeister.org/news/learn2quote.html
I feel sorry, but I am not able to understand what exactly you want to
do.
--
Herfried K. Wagner [MVP]
<URL:http://dotnet.mvps.org/>
It has something to do with the fact that you''re referencing the array
index [i.e.- s(i)] and also implicitly dimensioning your array by
specifying values for the indices [i.e. - (test) which is erroneous,
by-the-by]
Try this:
Option Strict On
Dim s() As String
Dim sTmp As String = "test"
Dim i As Integer
s(i) = "test"
--or--
s(i) = sTmp
-----
As a side note, if you wanted to create an array, and not dimension it
directly, you could say:
Dim s() As String = { "One", "Two", "Three" }
Hope this helped
J.
--
The email address listed is not my real address. Please do not send
valid email to that address.
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