问题描述
以下代码适用于带有和不带优化的Visual Studio 2008。但它只适用于没有优化(O0)的g ++。
The below code works on Visual Studio 2008 with and without optimization. But it only works on g++ without optimization (O0).
#include <cstdlib>
#include <iostream>
#include <cmath>
double round(double v, double digit)
{
double pow = std::pow(10.0, digit);
double t = v * pow;
//std::cout << "t:" << t << std::endl;
double r = std::floor(t + 0.5);
//std::cout << "r:" << r << std::endl;
return r / pow;
}
int main(int argc, char *argv[])
{
std::cout << round(4.45, 1) << std::endl;
std::cout << round(4.55, 1) << std::endl;
}
输出应为:
4.5
4.6
与优化( O1
- O3
)将输出:
But g++ with optimization (O1
- O3
) will output:
4.5
4.5
code> volatile 关键字在t之前,它的工作原理,所以可能会有某种优化bug吗?
If I add the volatile
keyword before t, it works, so might there be some kind of optimization bug?
在g ++ 4.1上测试。 2和4.4.4。
Test on g++ 4.1.2, and 4.4.4.
以下是ideone的搜索结果:
Here is the result on ideone:http://ideone.com/Rz937
我在g ++上测试的选项很简单:
And the option I test on g++ is simple:
g++ -O2 round.cpp
,即使我在Visual Studio 2008上打开 / fp:fast
选项,结果仍然是正确的。
The more interesting result, even I turn on /fp:fast
option on Visual Studio 2008, the result still is correct.
strong>进一步的问题:
Further question:
我想知道,是否应该始终打开 -ffloat-store
选项?
I was wondering, should I always turn on the -ffloat-store
option?
因为我测试的g ++版本是随 / 5和CentOS / Redhat 6 。
Because the g++ version I tested is shipped with CentOS/Red Hat Linux 5 and CentOS/Redhat 6.
我在这些平台下编译了许多程序,我担心会在我的程序中导致意外的错误。看起来有点难以调查所有我的C ++代码和使用的库,无论他们是否有这样的问题。任何建议?
I compiled many of my programs under these platforms, and I am worried it will cause unexpected bugs inside my programs. It seems a little difficult to investigate all my C++ code and used libraries whether they have such problems. Any suggestion?
有人对为什么甚至 / fp:fast
开启感兴趣,Visual Studio 2008仍然工作?看起来Visual Visual Studio 2008在这个问题上比g ++更可靠?
Is anyone interested in why even /fp:fast
turned on, Visual Studio 2008 still works? It seems like Visual Studio 2008 is more reliable at this problem than g++?
推荐答案
Intel x86处理器使用80位扩展精度在内部,而 double
通常为64位宽。不同的优化级别影响CPU的浮点值保存到内存中的频率,从而从80位精度到64位精度。
Intel x86 processors use 80-bit extended precision internally, whereas double
is normally 64-bit wide. Different optimization levels affect how often floating point values from CPU get saved into memory and thus rounded from 80-bit precision to 64-bit precision.
使用<$ c $
或者,使用<$ c $
Alternatively, use the long double
type, which is normally 80-bit wide on gcc to avoid rounding from 80-bit to 64-bit precision.
man gcc
说:
-ffloat-store
Do not store floating point variables in registers, and inhibit
other options that might change whether a floating point value is
taken from a register or memory.
This option prevents undesirable excess precision on machines such
as the 68000 where the floating registers (of the 68881) keep more
precision than a "double" is supposed to have. Similarly for the
x86 architecture. For most programs, the excess precision does
only good, but a few programs rely on the precise definition of
IEEE floating point. Use -ffloat-store for such programs, after
modifying them to store all pertinent intermediate computations
into variables.
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