如何使用正则表达式与find命令？

问题描述

我有一些用生成的uuid1字符串命名的图像。例如81397018-b84a-11e0-9d2a-001b77dc0bed.jpg。我想用find命令找出所有这些图片：

I have some images named with generated uuid1 string. For example 81397018-b84a-11e0-9d2a-001b77dc0bed.jpg. I want to find out all these images using "find" command:

find . -regex "[a-f0-9\-]\{36\}\.jpg".

但是不行。正则表达式有什么问题？有人可以帮我吗？

But it doesn't work. Something wrong with the regex? Could someone help me with this?

推荐答案

find . -regextype sed -regex ".*/[a-f0-9\-]\{36\}\.jpg"

请注意，您需要在开头指定。* / ，因为 find 匹配整个路径。

Note that you need to specify .*/ in the beginning because find matches the whole path.

例子：

Example:

susam@nifty:~/so$ find . -name "*.jpg"
./foo-111.jpg
./test/81397018-b84a-11e0-9d2a-001b77dc0bed.jpg
./81397018-b84a-11e0-9d2a-001b77dc0bed.jpg
susam@nifty:~/so$ 
susam@nifty:~/so$ find . -regextype sed -regex ".*/[a-f0-9\-]\{36\}\.jpg"
./test/81397018-b84a-11e0-9d2a-001b77dc0bed.jpg
./81397018-b84a-11e0-9d2a-001b77dc0bed.jpg

我的find ：

My version of find:

$ find --version
find (GNU findutils) 4.4.2
Copyright (C) 2007 Free Software Foundation, Inc.
License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html>
This is free software: you are free to change and redistribute it.
There is NO WARRANTY, to the extent permitted by law.

Written by Eric B. Decker, James Youngman, and Kevin Dalley.
Built using GNU gnulib version e5573b1bad88bfabcda181b9e0125fb0c52b7d3b
Features enabled: D_TYPE O_NOFOLLOW(enabled) LEAF_OPTIMISATION FTS() CBO(level=0) 
susam@nifty:~/so$ 
susam@nifty:~/so$ find . -regextype foo -regex ".*/[a-f0-9\-]\{36\}\.jpg"
find: Unknown regular expression type `foo'; valid types are `findutils-default', `awk', `egrep', `ed', `emacs', `gnu-awk', `grep', `posix-awk', `posix-basic', `posix-egrep', `posix-extended', `posix-minimal-basic', `sed'.

这篇关于如何使用正则表达式与find命令？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！