本文介绍了如何将此代码放在循环中，这样我就不必继续打印相同的东西了。的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我正在Drjava做一个Tic Tac Toe游戏。我需要这方面的帮助。所以我不会把整个代码放在一个循环中，所以我不必一遍又一遍地打印相同的东西。
Hi, I am making a Tic Tac Toe game in Drjava. I need help with this thing. So i wont to put this entire code in a loop so I Dont have to keep printing the same thing over and over again.
<pre lang="Javascript">import java.util.Scanner;
public class TicTacToeArray {
public static void main(String[] args){
Scanner in = new Scanner(System.in);
int [] A1 = {0,1,2};
int [] A2 = {3,4,5};
int [] A3 = {6,7,8};
int [] A4 = {0,3,6};
int [] A5 = {1,4,7};
int [] A6 = {2,5,8};
int [] A7 = {0,4,8};
int [] A8 = {2,4,6};
System.out.println("Player #1: Please enter a number between 0-8");
int playerOne = in.nextInt();
if (playerOne == A1 [0]){
System.out.println(" | | ");
System.out.println(" X | 1 | 2 ");
System.out.println(" | | ");
System.out.println(" -------------------------------");
System.out.println(" | | ");
System.out.println(" 3 | 4 | 5 ");
System.out.println(" | | ");
System.out.println(" -------------------------------");
System.out.println(" | | ");
System.out.println(" 6 | 7 | 8 ");
System.out.println(" | | ");
}else if (playerOne ==A1 [2]){
System.out.println(" | | ");
System.out.println(" 0 | 1 | X ");
System.out.println(" | | ");
System.out.println(" -------------------------------");
System.out.println(" | | ");
System.out.println(" 3 | 4 | 5 ");
System.out.println(" | | ");
System.out.println(" -------------------------------");
System.out.println(" | | ");
System.out.println(" 6 | 7 | 8 ");
System.out.println(" | | ");
}else if (playerOne ==A2 [0]){
System.out.println(" | | ");
System.out.println(" 0 | 1 | 2 ");
System.out.println(" | | ");
System.out.println(" -------------------------------");
System.out.println(" | | ");
System.out.println(" X | 4 | 5 ");
System.out.println(" | | ");
System.out.println(" -------------------------------");
System.out.println(" | | ");
System.out.println(" 6 | 7 | 8 ");
System.out.println(" | | ");
}else if (playerOne ==A2 [1]){
System.out.println(" | | ");
System.out.println(" 0 | 1 | 2 ");
System.out.println(" | | ");
System.out.println(" -------------------------------");
System.out.println(" | | ");
System.out.println(" 3 | X | 5 ");
System.out.println(" | | ");
System.out.println(" -------------------------------");
System.out.println(" | | ");
System.out.println(" 6 | 7 | 8 ");
System.out.println(" | | ");
}else if (playerOne ==A2 [2]){
System.out.println(" | | ");
System.out.println(" 0 | 1 | 2 ");
System.out.println(" | | ");
System.out.println(" -------------------------------");
System.out.println(" | | ");
System.out.println(" 3 | 4 | X ");
System.out.println(" | | ");
System.out.println(" -------------------------------");
System.out.println(" | | ");
System.out.println(" 6 | 7 | 8 ");
System.out.println(" | | ");
}else if (playerOne ==A3 [0]){
System.out.println(" | | ");
System.out.println(" 0 | 1 | 2 ");
System.out.println(" | | ");
System.out.println(" -------------------------------");
System.out.println(" | | ");
System.out.println(" 3 | 4 | 5 ");
System.out.println(" | | ");
System.out.println(" -------------------------------");
System.out.println(" | | ");
System.out.println(" X | 7 | 8 ");
System.out.println(" | | ");
}else if (playerOne ==A3 [1]){
System.out.println(" | | ");
System.out.println(" 0 | 1 | 2 ");
System.out.println(" | | ");
System.out.println(" -------------------------------");
System.out.println(" | | ");
System.out.println(" 3 | 4 | 5 ");
System.out.println(" | | ");
System.out.println(" -------------------------------");
System.out.println(" | | ");
System.out.println(" 6 | X | 8 ");
System.out.println(" | | ");
}else if (playerOne ==A3 [2]){
System.out.println(" | | ");
System.out.println(" 0 | 1 | 2 ");
System.out.println(" | | ");
System.out.println(" -------------------------------");
System.out.println(" | | ");
System.out.println(" 3 | 4 | 5 ");
System.out.println(" | | ");
System.out.println(" -------------------------------");
System.out.println(" | | ");
System.out.println(" 6 | 7 | X ");
System.out.println(" | | ");
}else {
System.out.println("Try Again");
}
}
}推荐答案
import java.util.Scanner;
public class TTT
{
public static void draw_tiles(int x)
{
int c, r; // r is the row number, c is the column number
for (r = 0; r < 3; ++r)
{
System.out.println(" | | ");
for ( c = 0; c < 3; ++c)
{
String sep, no;
int n = r * 3 + c;
sep = c < 2 ? "|" : "\n";
System.out.print(" ");
no = x == n ? "X" : String.valueOf(n);
System.out.print(no);
System.out.print(" ");
System.out.print(sep);
}
System.out.println(" | | ");
if ( r < 2 ) System.out.println("----------------------------------");
}
}
public static void main(String[] args)
{
Scanner in = new Scanner(System.in);
System.out.println("Player #1: Please enter a number between 0-8");
int playerOne = in.nextInt();
if ( playerOne >= 0 && playerOne <= 8)
draw_tiles(playerOne);
else
System.out.println("Try Again");
}
}
这篇关于如何将此代码放在循环中，这样我就不必继续打印相同的东西了。的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！