问题描述
我正在创建一个简单的程序,它将尝试从磁盘读取conf / conf.xml,但如果此文件或目录不存在则会创建它们。
I'm creating a simple program that will try to read in "conf/conf.xml" from disk, but if this file or dir doesn't exist will instead create them.
我可以使用以下代码执行此操作:
I can do this using the following code:
// create subdirectory path
Path confDir = Paths.get("./conf");
// create file-in-subdirectory path
Path confFile = Paths.get("./conf/conf.xml");
// if the sub-directory doesn't exist then create it
if (Files.notExists(confDir)) {
try { Files.createDirectory(confDir); }
catch (Exception e ) { e.printStackTrace(); }
}
// if the file doesn't exist then create it
if (Files.notExists(confFile)) {
try { Files.createFile(confFile); }
catch (Exception e ) { e.printStackTrace(); }
}
我的问题是,这真的是最优雅的方式吗?在新的子目录中创建一个新文件只需要创建两个简单的路径就好了。
My questions is if this really the most elegant way to do this? It seems superflous to need to create two Paths simple to create a new file in a new subdirectory.
推荐答案
你可以声明你的 confFile
as File
而不是 Path
。然后你可以使用 confFile.getParentFile()。mkdirs();
,见下面的例子:
You could declare your confFile
as File
instead of Path
. Then you can use confFile.getParentFile().mkdirs();
, see example below:
// ...
File confFile = new File("./conf/conf.xml");
confFile.getParentFile().mkdirs();
// ...
或者,按原样使用您的代码,你可以使用:
Or, using your code as is, you can use:
Files.createDirectories(confFile.getParent());
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