本文介绍了当我点击gridview gridview值的编辑按钮在文本框中重试时如何可能的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
<div>
<table>
<tr>
<td>Country Name</td>
<td>
<asp:DropDownList ID="ddlstCountry" runat="server" Width="100%">
</asp:DropDownList>
</td>
</tr>
<tr>
<td>State Name</td>
<td style="margin-left: 80px">
<asp:TextBox ID="txtState" runat="server" Width="100%"></asp:TextBox>
</td>
</tr>
<tr>
<td>
</td>
<td>
<asp:Button ID="btnSubmit" runat="server" Text="Submit"
onclick="btnSubmit_Click" />
</td>
</tr>
</table>
<asp:GridView ID="GvState" runat="server" AutoGenerateColumns="False"
DataKeyNames="StateId" Width="30%" onrowcommand="GvState_RowCommand">
<RowStyle HorizontalAlign="Center" />
<Columns>
<asp:TemplateField HeaderText="StateId">
<ItemTemplate>
<asp:Label ID="lblStateId" runat="server" Text='<%# Eval("StateId") %>'></asp:Label>
</ItemTemplate>
</asp:TemplateField>
<asp:TemplateField HeaderText="StateName">
<ItemTemplate>
<asp:Label ID="lblStateName" runat="server" Text='<%# Eval("StateName") %>'></asp:Label>
</ItemTemplate>
</asp:TemplateField>
<asp:TemplateField HeaderText="CountryName">
<ItemTemplate>
<asp:Label ID="lblCountryName" runat="server" Text='<%# Eval("CountryName") %>'></asp:Label>
</ItemTemplate>
</asp:TemplateField>
<asp:TemplateField HeaderText="Action">
<ItemTemplate>
<table>
<tr>
<td>
<asp:ImageButton ID="imgbtnEdit" runat="server" ImageUrl="~/Image/Edit.jpg"
CommandName="Edit" ToolTip="Edit" Width="25px" />
<asp:ImageButton ID="imgbtnDelete" runat="server" ImageUrl="~/Image/Delete.jpg"
CommandName="Delete" ToolTip="Delete" Width="25px" /></td>
</tr>
</table>
</ItemTemplate>
</asp:TemplateField>
</Columns>
</asp:GridView>
</div>
推荐答案
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