向gridview添加新行

问题描述

我正在一个项目中，该项目将上传excelfile
和所有的Excel工作表名称都绑定到一个下拉列表，我想选择一个excelshhet并添加到gridview，这将向网格添加诸如excelname，行数和数字列以及sheetname等的详细信息.一旦我从下拉列表中选择了另一个工作表
我需要在第一行下方添加工作表的相同详细信息...
我为一张工作表编写了代码，如何在第一行的下面将下一个工作表详细信息添加到gridview

Hi ,
am working on a project which will upload excelfile
and all the excel sheets names are bind to a dropdown,i want to select a excelshhet and add to gridview which will add details like excelname,number of rows and number columns and sheetname etc.. to grid and once i select another sheet from dropdown
i need to add same details of the sheet below the first row .....
i written code for one sheet ,how to add next sheet details to gridview ,below the first row

string ds = Session["nam"].ToString();
        string conStr = "Provider=Microsoft.Jet.OLEDB.4.0;" + "Data Source=" + ds + ";" + "Extended Properties=Excel 8.0;";

        OleDbConnection con = new OleDbConnection(conStr);
        con.Open();
        System.Data.DataTable dt = null;
        dt = con.GetOleDbSchemaTable(OleDbSchemaGuid.Tables, null);
        if (dt == null)
        {
            Response.Write("no shhet found"); ;
        }
 DataTable table = new DataTable();
        //DataRow dr = null;

        DataRow row=null;
        DataColumn column = new DataColumn();
        column.DataType = System.Type.GetType("System.String");
        column.ColumnName = "id";
        table.Columns.Add(column);

        column = new DataColumn();
        column.DataType = System.Type.GetType("System.String");
        column.ColumnName = "item";
        table.Columns.Add(column);

        column = new DataColumn();
        column.DataType = System.Type.GetType("System.String");
        column.ColumnName = "item2";
        table.Columns.Add(column);

        column = new DataColumn();
        column.DataType = System.Type.GetType("System.String");
        column.ColumnName = "item3";
        table.Columns.Add(column);
        OleDbDataAdapter adapter = new OleDbDataAdapter("SELECT * FROM [" + DropDownList1.SelectedItem.ToString() + "]", con);

        DataSet objDataSet = new DataSet();
        DataTable dt1 = new DataTable();
        adapter.Fill(objDataSet);
        dt1 = objDataSet.Tables[0];
        adapter.Fill(dt1);
        row = table.NewRow();
        int number_of_columns = dt1.Columns.Count;
       // Response.Write(number_of_columns);
        int number_of_rows = objDataSet.Tables[0].Rows.Count / 2;
        row["item"] = DropDownList1.SelectedItem.ToString();
        row["item2"] = number_of_rows;
        row["item3"] = number_of_columns;
        row["id"] = LabelUpload.Text;

       // table.NewRow();
        table.Rows.Add(row);

       //table.Rows.Add(table.NewRow());
        GridView1.DataSource =table;

        GridView1.DataBind();

推荐答案

DataRow newRow = dt.NewRow();
newRow[NAME] = "New row";
dt.Rows.Add(newRow);

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