为什么有人想要超载& （address-of）运算符？

问题描述

我只是读了，我不禁想到：

为什么任何人都想重载& （address-of）运算符？ >

 
 some_class * operator&（）const {return  address_of_object ; } 
 
 
 
 
有没有合法用例？
解决方案
 
如果你正在处理任何类型的包装器对象，你可能想要或需要透明地将包装器的访问转发到包含的对象。在这种情况下，您不能返回指向包装器的指针，但需要重载address-of运算符以返回指向包含对象的指针。
 
I just read this question, and I can't help but wonder:

Why would anyone possibly want to overload the & ("address-of") operator?
   some_class* operator&() const { return address_of_object; }
Is there any legitimate use case?
 解决方案 
If you're dealing with any sort of wrapper objects, you might want or need to transparently forward the access to the wrapper to the contained object. In that case, you can't return a pointer to the wrapper, but need to overload the address-of operator to return a pointer to the contained object.
                        
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