问题描述
我想检测RGB中最大的值.我怎么能发现呢?我想显示哪种颜色出现的次数最多RGB值.例如,在图像中,红色的出现率最高,因此它将显示为红色,其值以百分比表示.
I want to detect which value is maximum from RGB. how can I detect that?I want to display which colour has highest occurrence with theirRGB value. For example, In a image the RED colour has highest occurrence so it will display colour as RED and with their value in percentage.
我已经尝试通过获取图像的行和列来进行尝试,如下所示:
I have tried it by getting rows and cols of image like below:
public Mat onCameraFrame(CvCameraViewFrame cvf) {
mRgba = cvf.rgba();
int rows = mRgba.rows();
int cols = mRgba.cols();
// int ch = mRgba.channels();
double R=0,G=0,B=0;
for (int i=0; i<rows; i++)
{
for (int j=0; j<cols; j++)
{
double[] data = mRgba.get(i, j); //Stores element in an array
R = data[0];
G= data[1];
B = data[2];
}
}
Imgproc.putText(mRgba,"R:"+R + "G:"+G +"B:"+B,new Point(10,52),Core.FONT_HERSHEY_COMPLEX,.7,new Scalar(5,255,255), 2,8,false );
return mRgba;
}
,但是要花很多时间,并且屏幕滞后,因为我已经在onCameraFrame
中实现了代码.那么如何用这种方法快速检测到它,哪种是最好的方法呢?
but it is taking to much time and screen is lagging because I have implemented code in onCameraFrame
. So how can I detect it fast in this method and which is the best way to it?
谢谢.
推荐答案
将图像分为R,G和B通道,并计算每个Mat的总和.
Split the image into its R, G and B channels, and compute the sum of each Mat.
vector<Mat> channels;
split(mRgba, channels);
B = sum(channels[0])[0];
G = sum(channels[1])[0];
R = sum(channels[2])[0];
比较R,G和B的值,以了解帧中哪种颜色出现最多.
Compare the values of R, G and B to know which colour has occurred the most in the frame.
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