问题描述
我试图使用 bool比较(节点a,节点b)声明一个优先级节点作为比较器函数(它在节点类之外)。
I'm trying to declare a priority_queue of nodes, using bool Compare(Node a, Node b) as the comparator function (which is outside the node class).
我目前拥有的是:
priority_queue<Node, vector<Node>, Compare> openSet;
出于某种原因,我得到错误:比较类型名称
For some reason, I'm getting Error: "Compare" is not a type name
将声明更改为 priority_queue< Node,vector< Node> ;, bool Compare& code>
Changing the declaration to priority_queue <Node, vector<Node>, bool Compare>
给我错误:预期a>'
我也尝试过:
priority_queue<Node, vector<Node>, Compare()> openSet; priority_queue<Node, vector<Node>, bool Compare()> openSet; priority_queue<Node, vector<Node>, Compare<Node, Node>> openSet;
如何正确声明我的 priority_queue ?
推荐答案
您应该声明一个类比较和重载 operator(),如下所示:
You should declare a class Compare and overload operator() for it like this:
class Foo { }; class Compare { public: bool operator() (Foo, Foo) { return true; } }; int main() { std::priority_queue<Foo, std::vector<Foo>, Compare> pq; return 0; }
或者,如果由于某些原因不能作为类,可以使用 std :: function :
Or, if you for some reasons can't make it as class, you could use std::function for it:
class Foo { }; bool Compare(Foo, Foo) { return true; } int main() { std::priority_queue<Foo, std::vector<Foo>, std::function<bool(Foo, Foo)>> pq(Compare); return 0; }
这篇关于使用自定义比较器在c ++中声明priority_queue的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!