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问题描述

您好,我尝试创建一个列表,显示一个包含员工的简单列表框( medewerkers ),但是我收到错误:



CS0120非静态字段,方法或属性需要对象引用'Verzamel.GetAllMedewerkers(string)'



Hello, i try to create a list that displays a simple listbox with employees (medewerkers), however i receive the error:

CS0120An object reference is required for the non-static field, method, or property 'Verzamel.GetAllMedewerkers(string)'

<public void LoadMedewerkers()
        {

           lblMedewerkers.Items.Clear();


            string filter = "";
            List<medewerkers> medewerkers = Verzamel.GetAllMedewerkers(filter);


            foreach (Medewerkers s in medewerkers)
            {
                lblMedewerkers.Items.Add(s);
            }
        }





Verzamel.GetAllMedewerkers引用此类:





Verzamel.GetAllMedewerkers is referenced to this class:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Configuration;
using System.Data.SqlClient;
using System.Windows.Forms;

namespace TimeReg
{
    class Verzamel
    {

        private static string connectionString = ConfigurationManager.ConnectionStrings["TimeReg.Properties.Settings.TimeRegConnectionString"].ConnectionString;
        private SqlConnection conn = new SqlConnection(connectionString);


        List<medewerkers> medewerkers = new List<medewerkers>();


       public List<medewerkers> GetAllMedewerkers(string filter)
        {

            medewerkers = new List<medewerkers>();


            string query = "SELECT M.* FROM Medewerkers M";

            if (filter != "")
            {
                query += " WHERE Voornaam LIKE '%" + filter + "%' OR Achternaam LIKE '%" + filter + "%'";
            }


            conn.Open();
            SqlCommand cmd = new SqlCommand(query, conn);


            using (SqlDataReader reader = cmd.ExecuteReader())
            {
                while (reader.Read())
                {

                    Medewerkers Medewerker = new Medewerkers();


                    Medewerker.Personeelsnummer = reader.GetInt32(0);
                    Medewerker.LoginID = reader.GetInt32(1);
                    Medewerker.Voornaam = reader.GetString(2);
                    Medewerker.Tussenvoegsel = reader.GetString(3);
                    Medewerker.Achternaam = reader.GetString(4);


                    medewerkers.Add(Medewerker);
                }
            }

            conn.Close();
            return medewerkers;
        }
    }
}





我尝试了什么:



如何修复此问题,我确实尝试将列表更改为静态,但似乎无法正常工作。



我需要做什么?



任何帮助都是适用的。



提前致谢。



What I have tried:

How can i fix this, i did try to add change the list to static, but it does not seems to work.

What do i need to do?

Any help is appriciated.

Thanks in advance.

推荐答案

// Create an instance of the Verzamel class 
//  (or use an already existing instance)
//
Verzamel verz = new Verzamel();
// Use the instance to call a member function
List<medewerkers> medewerkers = verz.GetAllMedewerkers(filter);

或者使函数 static 。然后你可以像以前一样打电话。



Alternatively make the function static. Then you can call it as before.

public static List<medewerkers> GetAllMedewerkers(string filter)
{
    // Must use a local variable instead of the class member when
    //  this method is static and the member variable is not static
    List<medewerkers> medewerkers = new List<medewerkers>();

    // Similar for conn but not for connectionString which is static
    SqlConnection conn = new SqlConnection(connectionString);

    // ...
    return medewerkers;
}

[/ EDIT]

[/EDIT2]


引用:

这是一个错误,说对象引用不在一个对象上,我在

This is an error that says objectreference is not on an object, i get this on the

上得到这个

这是我们被问到的最常见问题之一,也是一个我们最没有能力回答,但你最有能力回答自己。



让我解释一下错误的含义:你试图使用变量,属性,或方法返回值,但它包含null - 这意味着变量中没有类的实例。

它有点像一个口袋:你的衬衫里有一个口袋,你呢用来握笔。如果你进入口袋并发现那里没有笔,你就不能在一张纸上签名 - 如果你尝试的话,你会得到非常有趣的外观!空口袋给你一个空值(这里没有笔!)所以你不能做任何你检索笔通常做的事情。它为什么空?这就是问题 - 可能是你今天早上离开家时忘了拿起你的笔,或者你昨晚把它拿到昨天的衬衫口袋里时可能会把笔留下来。



我们无法分辨,因为我们不在那里,更重要的是,我们甚至看不到你的衬衫,更不用说口袋里的东西了!



回到计算机,你做了同样的事情,不知何故 - 我们看不到你的代码,更不用说运行它了,找不到包含null的东西。

但是你可以 - 而Visual Studio将在这里帮助你。在调试器中运行您的程序,当它失败时,VS将向您显示它发现问题的行。然后,您可以开始查看它的各个部分,以查看哪个值为null,并开始回顾代码以找出原因。因此,在包含错误行的方法的开头放置一个断点,然后从头再次运行程序。这一次,VS会在错误发生前停止,让你通过查看代码来查看你的价值来检查发生了什么。



但我们做不到那 - 我们没有您的代码,如果我们拥有它,我们不知道如何使用它,我们没有您的数据。所以尝试一下 - 看看你能找到多少信息!


This is one of the most common problems we get asked, and it's also the one we are least equipped to answer, but you are most equipped to answer yourself.

Let me just explain what the error means: You have tried to use a variable, property, or a method return value but it contains null - which means that there is no instance of a class in the variable.
It's a bit like a pocket: you have a pocket in your shirt, which you use to hold a pen. If you reach into the pocket and find there isn't a pen there, you can't sign your name on a piece of paper - and you will get very funny looks if you try! The empty pocket is giving you a null value (no pen here!) so you can't do anything that you would normally do once you retrieved your pen. Why is it empty? That's the question - it may be that you forgot to pick up your pen when you left the house this morning, or possibly you left the pen in the pocket of yesterdays shirt when you took it off last night.

We can't tell, because we weren't there, and even more importantly, we can't even see your shirt, much less what is in the pocket!

Back to computers, and you have done the same thing, somehow - and we can't see your code, much less run it and find out what contains null when it shouldn't.
But you can - and Visual Studio will help you here. Run your program in the debugger and when it fails, VS will show you the line it found the problem on. You can then start looking at the various parts of it to see what value is null and start looking back through your code to find out why. So put a breakpoint at the beginning of the method containing the error line, and run your program from the start again. This time, VS will stop before the error, and let you examine what is going on by stepping through the code looking at your values.

But we can't do that - we don't have your code, we don't know how to use it if we did have it, we don't have your data. So try it - and see how much information you can find out!


static class Verzamel
{
    private static readonly string connectionString = ConfigurationManager.ConnectionStrings["TimeReg.Properties.Settings.TimeRegConnectionString"].ConnectionString;

    public static List<Medewerkers> GetAllMedewerkers(string filter)
    {
        List<Medewerkers> medewerkers = new List<Medewerkers>();

        using (SqlConnection conn = new SqlConnection(connectionString))
        using (SqlCommand cmd = new SqlCommand("", conn))
        {
            string query = "SELECT M.Personeelsnummer, M.LoginID, M.Voornaam, M.Tussenvoegsel, M.Achternaam FROM Medewerkers M";

            if (!string.IsNullOrEmpty(filter))
            {
                query += " WHERE M.Voornaam LIKE @filter OR M.Achternaam LIKE @filter";
                cmd.Parameters.AddWithValue("@filter", "%" + filter + "%");
            }

            cmd.CommandText = query;

            conn.Open();
            using (SqlDataReader reader = cmd.ExecuteReader())
            {
                while (reader.Read())
                {
                    medewerkers.Add(new Medewerkers
                    {
                        Personeelsnummer = reader.GetInt32(0),
                        LoginID = reader.GetInt32(1),
                        Voornaam = reader.GetString(2),
                        Tussenvoegsel = reader.GetString(3),
                        Achternaam = reader.GetString(4),
                    });
                }
            }
        }

        return medewerkers;
    }
}




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Everything you wanted to know about SQL injection (but were afraid to ask) | Troy Hunt[^]
How can I explain SQL injection without technical jargon? | Information Security Stack Exchange[^]
Query Parameterization Cheat Sheet | OWASP[^]


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07-23 06:28
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