在F#中明确指定参数类型

问题描述

我正在编写一个F#函数，该函数将数字分解为素数.

I'm writing an F# function that factorises a number into prime factors.

let factors primes i =
    let mutable j = i
    for p in primes do
        while (j>1) && (j%p=0) do
            j <- j/p
            printfn "prime: %i" p

它适用于i的int值，但不适用于int64值.参数primes是一组int值.

It works for int values of i, but not int64 values. The parameter primes is a set of int values.

我理解为什么会这样-类型推断是假设函数仅使用int参数-但我想将参数类型明确指定为int64.

I understand why this is the case - type inference is assuming that the function only takes int parameters - but I want to explicitly specify the parameter type as int64.

是否可以编写此函数以便它对int和int64均适用?

Is it possible to write this function so that it will work for both int and int64?

推荐答案

如果只想使用int64值，只需将1和0分别替换为1L和0L. jpalmer的答案涵盖了一般情况.

If you want to work only on int64 values, just replace 1 and 0 with 1L and 0L respectively. jpalmer's answer covers the generic case.

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