退出带有特定字符串的方法

问题描述

我在Java领域还比较陌生，并且正在为一个类编写程序.我已经对所有代码进行了编码，并且运行良好，但是当我键入字符串"exit"时，我需要退出一个方法.我当前的代码将在下面.我必须按照作业分配3种方法(包括main)和一个"while"循环(或do-while，但我的教授禁止我们使用这些方法).这是一个魔术八球"程序，while循环设置为继续询问问题，直到用户键入"exit"为止，但我似乎无法让我的"while"循环正常工作.如果我输入exit作为第一个字符串，它将像预期的那样退出，但是，如果我键入任何其他字符串，即使我键入exit，它也将继续运行，并且基本上变成一个无限循环的问题/答案.感谢您的帮助.

I'm still relatively new at Java and am working on a program for class. I have everything coded up and it's working great, but I need to exit a method when I type the string "exit". My current code will be below. I must have 3 methods (includes main) and a "while" loop (or do-while, but my professor has barred us from using those) as per the assignment. It's a "magic eight ball" program and the while loop is set to continue asking questions until the user types "exit" but I can't seem to get my "while" loop to work correctly. If I type exit as the first string it'll exit like it's supposed to, but if I type any other string it'll keep running, even after I type exit, and basically becomes an infinite loop of questions/answers. Any help is appreciated.

请注意，switch语句中的这些数字纯粹是用于将来答案的占位符，因此请忽略它们.

A side note, those numbers in the switch statement are purely place holders for future answers, so ignore them.

import java.util.*;

public class FirstProblem {
    public static void main (String [] args) {
        getQuestion();
    }

    public static String getQuestion () {
        Scanner input = new Scanner (System.in);
        System.out.print ("Ask any question you need answered and prepare yourself for the sage advice of......your computer.\nJust type \"exit\" when you can't handle the truth any longer.\nQuestion: ");
        String question = input.nextLine();
        String exit = "exit";
        showAnswer();
        while (!question.equals(exit)) {
            getQuestion();
        }
        return question;
    }

    public static void showAnswer () {
        int answer = (int)(Math.random() * 10);
        switch (answer) {
            case 0: System.out.println ("1"); break;
            case 1: System.out.println ("2"); break;
            case 2: System.out.println ("3"); break;
            case 3: System.out.println ("4"); break;
            case 4:System.out.println ("5"); break;
            case 5:System.out.println ("6"); break;
            case 6:System.out.println ("7"); break;
            case 7: System.out.println ("8"); break;
            case 8: System.out.println ("9"); break;
            case 9: System.out.println ("10"); break;
        }
        return;
    }
}

推荐答案

您的问题在以下代码中:

Your problem is in this code:

        showAnswer();
        while (!question.equals(exit)) {
            getQuestion();
        }

如果您不知道在此处进行什么递归操作，则可以进行递归调用，网址为维基百科

This is doing a recursive call, if you don't know what recursion is read about it here at Wikipedia

解决方案是将其更改为:

The solution would be to change it to:

        while (!question.equals(exit)) {
            showAnswer();
            System.out.print("Question: ");
            question = input.nextLine();
        }

这是Ideone上的代码段.

Here's the code snippet on Ideone.

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