如何确定数字是否为任何类型的int(核心或numpy，带符号或非带符号)?

问题描述

我需要测试变量是否为类型int或np.int*，np.uint*中的任何一个，最好使用单个条件( ie 否or).

I need to test whether a variable is of type int, or any of np.int*, np.uint*, preferably using a single condition (i.e. no or).

经过一些测试，我想:

• isinstance(n, int)仅匹配int和np.int32(或np.int64取决于平台)，
• np.issubdtype(type(n), int)似乎与所有int和np.int*都匹配，但与np.uint*不匹配.

• isinstance(n, int) will only match int and np.int32 (or np.int64 depending on plateform),
• np.issubdtype(type(n), int) seems to match all int and np.int*, but doesn’t match np.uint*.

这导致两个问题:np.issubdtype是否会匹配任何种带符号的整数?可以一次检查数字是否为带符号的整数或无符号的整数吗?

This leads to two questions: will np.issubdtype match any kind of signed ints? Can determine in a single check whether a number is any kind of signed or unsigned int?

这是关于测试 integers 的，测试应返回False浮点型.

This is about testing for integers, the test should return False for float-likes.

推荐答案

NumPy提供了您可以/应该用于子类型检查的基类，而不是Python类型.

NumPy provides base classes that you can/should use for subtype-checking, rather than the Python types.

使用np.integer检查有符号整数或无符号整数的任何实例.

Use np.integer to check for any instance of either signed or unsigned integers.

使用np.signedinteger和np.unsignedinteger检查带符号类型或无符号类型.

Use np.signedinteger and np.unsignedinteger to check for signed types or unsigned types.

>>> np.issubdtype(np.uint32, np.integer)
True
>>> np.issubdtype(np.uint32, np.signedinteger)
False
>>> np.issubdtype(int, np.integer)
True

经过测试，所有浮点或复数类型都将返回False.

All floating or complex number types will return False when tested.

np.issubdtype(np.uint*, int)始终为False，因为Python int是带符号类型.

np.issubdtype(np.uint*, int) will always be False because the Python int is a signed type.

在文档此处.

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