本文介绍了指数在PHP数组推动元件和移动previous元的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
这是我的数组。我想在索引3推的元件,并在同一时间移动至previous元件下。 请阅读第一它不是array_splice()工作
This is my array. I want to push an element at index 3 and at the same time move the previous element to next. Please read first its not array_splice() work
array(6) {
[0]=>
string(1) "One_test"
[1]=>
string(1) "Two_test"
[2]=>
string(1) "Three_test"
[3]=>
string(1) "Four_test"
[4]=>
string(1) "Five_test"
[5]=>
string(1) "Six_test"
}
所以,我期望的输出是
So my desired output is
array(6) {
[0]=>
string(1) "One_test"
[1]=>
string(1) "Two_test"
[2]=>
string(1) "Three_test"
[3]=>
string(1) "Six_test"
[4]=>
string(1) "Four_test"
[5]=>
string(1) "Five_test"
}
所以看到我需要用 5
索引元素,然后替换 3
索引元素的移动previously 3
索引元素进入下一。最后,推元件(5)删除
So notice I need replace 3rd
indexed element with 5th
indexed element and then move previously 3rd
indexed element into next. Finally the pushed element (5th) to remove
任何想法?
推荐答案
从欺骗启发:
我会做一个 array_pop()
和 array_slice()
阵列上:
$original = array( 'a', 'b', 'c', 'd', 'e' );
$new_one = array_pop($original);
array_splice( $original, 3, 0, $new_one );
我的解决方案
所以前:
array(6) {
[0]=>
string(8) "One_test"
[1]=>
string(8) "Two_test"
[2]=>
string(10) "Three_test"
[3]=>
string(9) "Four_test"
[4]=>
string(9) "Five_test"
[5]=>
string(8) "Six_test"
}
和之后:
array(6) {
[0]=>
string(8) "One_test"
[1]=>
string(8) "Two_test"
[2]=>
string(10) "Three_test"
[3]=>
string(8) "Six_test"
[4]=>
string(9) "Four_test"
[5]=>
string(9) "Five_test"
}
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