问题描述
我正在尝试使用2D FFT将滤镜应用于图像。我有滤波器矩阵（卷积核等），但如果我想用fft我需要将滤波器和图像矩阵扩展到2平方矩阵的幂。
I am trying to apply filter to image using 2D FFT. I have filter matrix (convolution kernel etc), but if I want to use fft I need to expand filter and picture matrix to power of 2 square matrix.
首先我用零展开它（因此图像和滤波器的矩阵将位于2矩阵的大功率的左上角）我得到了这个结果
First I expand it with zeros (so matrix of picture and filter would be in top left corner of big power of 2 matrix) and I got this result
然后我尝试使用图像矩阵，当我应用没有fft的卷积时，填充图像矩阵，每边有滤波器尺寸/ 2，而不是带有简单扩展滤波器矩阵的填充矩阵，功率为2矩阵与fft卷积，我得到了这个
Then I tried what I did with picture matrix when I was applying convolution without fft, padded picture matrix with filter dimension/2 from each side, and than that padded matrix with simple expand filter matrix to power of 2 matrix to convolve with fft and i got this
这是原始图片。
关于算法：
我在两个扩展矩阵上应用2d fft，而在我做简单逆fft之后，我使用逐点乘法矩阵。此外，图像矩阵的编号从0到16M（前8位为红色，后8位为绿色，第3位为蓝色）
About algorithm:I am applying 2d fft on both expanded matrixes and than dotwise multiply matrixes after what Im doing simple inverse fft. Also picture matrix are number from 0 to 16M (first 8 bits are red, second 8 bits are green and third 8 bits are blue)
我认为问题正在进行中我如何将图片和滤波器矩阵扩展为2矩阵的平方功率，但我不确定。我测试了fft函数（fft和反fft，我有相同的图片（没有逐点乘法））
I think that problem is in way how I am expanding picture and filter matrix to square power of 2 matrix but im not sure. I tested fft functions (fft and inverse fft, i got same picture (without dotwise multiplication))
还过滤
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推荐答案
您无需一次性转换图像。
在子块上使用FFT。通过内核大小重叠转换后的子图像，并丢弃环绕瞬态（重叠保存）或添加输入和输入瞬态（重叠 - 添加）。
You don't need to transform the image all at once.Use FFTs on subblocks. Overlap the transformed subimages by the kernel size and either discard the wraparound transient (overlap-save) or add the input-on and input-off transients (overlap-add).
在尝试两个维度之前，先了解。
Understand fast convolution in one dimension before you try to do it in two.
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