当assert（）意外触发时，如何抑制Google测试中的终止？

问题描述

讨论了如何捕获失败的断言，例如你设置你的灯具，使assert（）失败，你看到不错的输出。但我需要的是相反的。我想测试assert（）成功。但如果它失败，我想有好的输出。

Here it's discussed how to catch failing assert, e.g. you setup your fixture so that assert() fails and you see nice output. But what I need is the opposite. I want to test that assert() succeeds. But in case it fails I want to have nice output. At that point it just terminates when it snags on assert().

#define LIMIT 5

struct Obj {
    int getIndex(int index) {
        assert(index < LIMIT);
        // do stuff;
    }
}

Obj obj;

TEST(Fails_whenOutOfRange) {
    ASSERT_DEATH(obj->getIndex(6), "");
}

TEST(Succeeds_whenInRange) {
    obj->getIndex(4);
}

上面是一个假设的例子。我想要第二个测试不会终止，万一它失败，例如如果我设置LIMIT为3.毕竟，ASSERT_DEATH在assert（）失败时会以某种方式终止。

Above is contrived example. I want second test not to terminate in case it fails, for example if I set LIMIT to 3. After all, ASSERT_DEATH suppresses somehow termination when assert() fails.

推荐答案

以下只是我的意见，但对我来说似乎你要么测试错误的东西，工具

The following is just my opinion, but it seems for me that you are either testing a wrong thing, or using a wrong tool.

Assert（C assert（））不用于验证输入，它用于捕获不可能的情况。例如，它将从发布代码中消失，因此您不能依赖它。

Assert (C assert()) is not for verifying input, it is for catching impossible situations. It will disappear from release code, for example, so you can't rely on it.

您应该测试的是您的函数比实现。您应该决定，您对无效输入值的规范是什么：

What you should test is your function specification rather than implementation. And you should decide, what is your specification for invalid input values:

• 未定义的行为，因此 assert

• Undefined behavior, so assert is fine, but you can't test it with unit-test, because undefined behavior is, well, undefined.

定义的行为。那么你应该是一致的，不管 NDEBUG 在场。在我看来，抛出异常是正确的事情，而不是调用 std :: abort ，这几乎是无用的用户（不能被拦截和正确处理）。

Defined behavior. Then you should be consistent regardless of NDEBUG presence. And throwing exception, in my opinion, is the right thing to do here, instead of calling std::abort, which is almost useless for user (can't be intercepted and processed properly).

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