C ++ pthread成员函数

本文介绍了C ++ pthread成员函数的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

我不能编译因为 pthread_create 行：

void* gtk_functor::_threaded_run(void* win)
{
    Gtk::Window* w = static_cast<Gtk::Window*>(win);
    Gtk::Main::run(*w);
    delete w;
}

void gtk_functor::operator ()(Gtk::Window& win, bool threaded)
{
    if (threaded)
    {
        pthread_t t_num;
        pthread_create(&t_num, NULL, (void* (*)(void*))&gtk_functor::_threaded_run, static_cast<void*>(&win));
    }
    else
    {
        Gtk::Main::run(win);
    }
}

此gcc行：

g ++ -o main'pkg-config --cflags --libs sqlite3 gtkmm-3.0'-lpthread main.cpp

使用此输出结束编译：

code/ui.cpp: In member function 'void ui::gtk_functor::operator()(Gtk::Window&, bool)':
code/ui.cpp:45:65: warning: converting from 'void* (ui::gtk_functor::*)(void*)' to 'void* (*)(void*)' [-Wpmf-conversions]

b $ b

显然代码不能正常工作，当 if（threaded） sementation fault

and apparently the code doesn't work correctly, I get sementation fault when the if (threaded) is raised.

我知道它与转换，但我不知道正确的形式传递一个成员函数到pthread_create。任何建议？

I know its with the cast, but I don't know the correct form of passing a member function into pthread_create. Any suggestions?

推荐答案

尝试 _threaded_run static。在标题中：

Try making _threaded_run static. In the header:

private:
  static void* _threaded_run(void*);

在实现中：

void* gtk_functor::_threaded_run(void* win) {
  Gtk::Window* w = static_cast<Gtk::Window*>(win);
  Gtk::Main::run(*w);
  delete w;
}

然后在创建线程时：

pthread_create(&t_num, NULL, &gtk_functor::_threaded_run, static_cast<void*>(&win));

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