问题描述
如何获取 char ？
的位数我知道 CHAR_BIT 来自 climits 。这被描述为»宏产生用于表示char类型的对象的位数的最大值。«at 。我知道这意味着 char 中的位数，不是吗？
I know about CHAR_BIT from climits. This is described as »The macro yields the maximum value for the number of bits used to represent an object of type char.« at Dikumware's C Reference. I understand that means the number of bits in a char, doesn't it?
结果与 std :: numeric_limits 不知何故？ std :: numeric_limits< char> :: digits 正确返回 7 ，但不幸的是，因为此值尊重8位字符在这里...
Can I get the same result with std::numeric_limits somehow? std::numeric_limits<char>::digits returns 7 correctly but unfortunately, because this value respects the signedness of the 8-bit char here…
推荐答案
如果你想过分具体，可以这样做：
If you want to be overly specific, you can do this:
sizeof(char) * CHAR_BIT
如果你知道你肯定要做sizeof char，它有点过分，因为sizeof（char）被保证为1。
If you know you are definitely going to do the sizeof char, it's a bit overkill as sizeof(char) is guaranteed to be 1.
但是如果你移动到不同的类型，如wchar_t，这将是重要的。
But if you move to a different type such as wchar_t, that will be important.
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