本文介绍了错误消息:“jj"的名称查找已更改为 ISO“for"范围,(如果您使用“-fpermissive",G++ 将接受您的代码)的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
错误是:
In function ‘int returnShortestWeightedBranch(std::vector<route, std::allocator<route> >*)’:
error: name lookup of ‘jj’ changed for ISO ‘for’ scoping
note: (if you use ‘-fpermissive’ G++ will accept your code)
代码是:
for (int i = 0; i< routeVector.size(); i++)
{
if (routeVector[i].exitPoint == exitPointDetailsVector[preserveL].exitPoint)
{
cout << "
-----------parent: " << routeVector[i].exitPoint;
branch obj;
obj.connectedExitPoint = exitPointDetailsVector[preserveI].exitPoint;
routeVector[i].selectedBranchesVector.push_back (obj);
for (int jj = 0; jj < routeVector[i].selectedBranchesVector.size(); jj++);
{
cout << "
-----------branch: " << routeVector[i].selectedBranchesVector[jj].connectedExitPoint;
}
}
}
这里有什么问题?
编辑 1:
我更改了以下内容:
for (int jj = 0; jj < routeVector[i].selectedBranchesVector.size(); jj++);
到:
int jj;
for (jj = 0; jj < routeVector[i].selectedBranchesVector.size(); jj++);
现在它开始工作了!!我不明白原因.
and now it is working!! I fail to understand the REASONS.
推荐答案
在内部 for 语句的末尾有一个分号.jj
的作用域到此结束,所以它在块内不可见.
You have a semicolon at the end of the inner for statement. That ends the scope of jj
there, so it is not visible inside the block.
编辑
你已经解决了范围问题,但你的 for 循环仍然只是执行
Edit
You have solved the scope problem, but still have your for loop executing just
<nothing>;
去掉括号后的分号!
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