问题描述
我对 Android 应用开发非常陌生.在我的新 Android 应用程序中,我想显示一些来自网络服务的数据.这意味着我有一个 SOAP 消息
,我需要解析来自 SOAP 响应的数据.在 iPhone 应用程序中,我非常了解解析 SOAP 消息响应,但是,在 android 中我不知道该怎么做?我在谷歌搜索了很多,得到了一些想法.但是,我对此非常困惑.任何人都可以提出任何最简单的方法来理解 SOAP 发送请求/接收响应并在 Android
中的 SAXParser
中解析(XML 格式
)响应?我已经在我的项目中安装了 ksoap2-android-assembly-2.6.0-jar-with-dependencies.jar
.在这里我找到了一些示例代码,我在这里发布,
Am very new to Android apps development. In my new Android app i want to show some data from webservice. This means i have a SOAP message
, i need to parse the data from SOAP response. In iPhone app i knew very well to parse SOAP message response but, in android i don't know how to do this? I searched lot in Google and get some ideas. But, am very confusing on this. Can anyone please suggest any easiest way to understand SOAP send request/receive response and parse(XML format
) the response in SAXParser
in Android
? I has installed ksoap2-android-assembly-2.6.0-jar-with-dependencies.jar
in my project. Here i found some sample code, i post here,
import java.io.*;
import org.ksoap2.SoapEnvelope;
import org.kxml2.io.KXmlParser;
import org.xmlpull.v1.XmlPullParserException;
public class ParsingSteps
{
public static void main(String[] args)
{
try{
// String msg="<hello>World!</hello>";
String msg = "<SOAP-ENV:Envelope " + "xmlns:SOAP-ENV="http://
www.w3.org/2001/12/soap-envelope" " + "xmlns:xsi="http://www.w3.org/
2001/XMLSchema-instance <http://www.w3.org/%0A2001/XMLSchema-instance>""
+"xmlns:xsd="http://www.w3.org/2001/
XMLSchema"& gt;" +
"<SOAP-ENV:Body>" +
"<result>" +
"<message xsi:type="xsd:string">Hello World</message>" +
"</result>" +
"</SOAP-ENV:Body>" +
"</SOAP-ENV:Envelope>";
// byte[] in= msg.getBytes();
KXmlParser parser=new KXmlParser();
parser.setInput(new StringReader(msg));
SoapEnvelope soapenvelope= new SoapEnvelope
(SoapEnvelope.VER12);
//soapenvelope.parse(parser);
soapenvelope.parseBody(parser);
}
catch (IOException e) {
System.out.println("Error reading URI: " + e.getMessage ());
} catch (XmlPullParserException e) {
System.out.println("Error in parsing: " + e.getMessage ());
}
// String result=parser.getName();
//System.out.println(result);
}
}
这是正确的代码.请对我的问题提出任何建议.请帮我解决这个问题.提前致谢.
Is this correct code. Please give any suggestion on my question. Please help me on this. Thanks in advance.
推荐答案
Google for Ksoap2 教程你会得到很多.这是向 Web 服务发送请求的示例代码.
Google for Ksoap2 tutorial u will get a lot of them . Here is sample code for sending request to web service .
public class WebServicePoc extends Activity{
private static final String SOAP_ACTION = "http://tempuri.org/Arnoid";
private static final String METHOD_NAME = "Arnoid";
private static final String NAMESPACE = "http://tempuri.org/";
private static final String URL = "http://ipaddress:port/UserAuthenticationInterfacer.asmx";
EditText editText;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
HashMap<String, String> a=new HashMap<String, String>();
try {
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
request.addProperty("FOSID", "1994");
request.addProperty("IMEINumber", "");
request.addProperty("SIMCardNo", "");
request.addProperty("ApplicationName", "App");
request.addProperty("CurrentVersion", "1.0.0.0");
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.dotNet=true;
envelope.setOutputSoapObject(request);
AndroidHttpTransport androidHttpTransport = new AndroidHttpTransport(URL);
androidHttpTransport.call(SOAP_ACTION, envelope);
SoapObject result = (SoapObject)envelope.getResponse();
editText=(EditText)findViewById(R.id.text1);
editText.setText(result.toString());
} catch (Exception e) {
e.printStackTrace();
}
对于 xml,请查看 xml 解析器的教程,仅使用 SAX,因为 android 不支持 STAX.对于发送 xml 请求,您可以将 xml 作为字符串发送,然后在服务器端解码.
And for xml pls check tutorial for xml parsers,use SAX only, as STAX is not supported in android . For sending xml request u can send xml as string and then decode on sever side .
这篇关于如何在Android中以XML格式发送SOAP请求和解析SOAP响应?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!