本文介绍了从StdIn读取字符的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
public class New
{
public static void main(String[] args)
{
System.out.println("Calculator");
float a = StdIn.readFloat();
char sign = StdIn.readChar();
float b = StdIn.readFloat();
float c = 0;
if (sign == '+') c = a+b;
else if (sign == '-') c = a-b;
else if (sign == 'x') c = a*b;
else if (sign == '/') c = a/b;
System.out.println(c);
}
}
代码,我试图做一个计算器,使用字符和float数据类型的StdIn输入。
I need some help with this bit of code, I'm attempting to make a calculator that takes StdIn input with both character and float data types.
推荐答案
Scanner
class。
像这样:
import java.util.Scanner;
public class New
{
public static void main(String[] args)
{
System.out.println("Calculator");
Scanner scanner = new Scanner(System.in);
System.out.println("Enter Parameter ");
System.out.print("a : ");
float a = scanner.nextFloat();
System.out.print("+|-|*|/: ");
String op = scanner.next();
System.out.print("b : ");
float b = scanner.nextFloat();
float c = 0;
switch (op)
{
case "+":
c = a + b;
break;
case "-":
c = a - b;
break;
case "*":
c = a * b;
break;
case "/":
c = a / b;
break;
default:
System.out.println("Illegal operant");
}
System.out.println("Result: " + c);
}
}
我添加了一个开关盒而不是else ifs。
I added a switch case instead of the else ifs.
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