本文介绍了如何与QUOT;洗牌"数组?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个艰难的时间试图创造一个shuffleDeck()方法。
我所要做的是创建一个将数组参数(这将是扑克牌)洗牌,并返回洗牌数组列表的方法。
这是code:
类卡
{
int值;
串套装;
字符串名称; 公共字符串的toString()
{
回报(名称+的+花色);
}
}公共类PickACard
{
公共静态无效的主要(字串[] args)
{
卡[] =甲板buildDeck();
//显示甲板(甲板); 诠释选择=(INT)(的Math.random()* deck.length);
卡挑=甲板[选择] 的System.out.println(你选择了一个+挑+出了甲板。);
的System.out.println(在大酒杯您的卡是值得+ picked.value +点); } 公共静态卡[] buildDeck()
{
的String [] =套装{俱乐部,钻石,心,黑桃};
的String []名= {ZERO,一,二,三,四有,五,六个一,七,八,九,十, 杰克,皇后,王,王牌}; INT I = 0;
卡[] =甲板新卡[52]; 对于(一个String:西服)
{
为(中间体V = 2; V族= 14; v ++)
{
卡C =新卡();
c.suit =秒;
c.name =名称[V]
如果(V == 14)
c.value = 11;
否则如果(ⅴ→10)
c.value = 10;
其他
c.value = V; 甲板[I] = C;
我++;
}
}
回到甲板上;
} 公共静态的String [] shuffleDeck(卡[]甲板)
{
/ **我试图得到两个索引号,并交换他们。
我试图找出如何循环会这样它种模拟洗牌。
* /
} 公共静态无效displayDeck(卡[]甲板)
{
对于(卡C:甲板)
{
的System.out.println(c.value +\\ t+ C);
}
}
}
解决方案
如何
列表<卡>清单= Arrays.asList(甲板);
Collections.shuffle(名单);
或者单行:
Collections.shuffle(Arrays.asList(DEC));
I am having a tough time trying to create a "shuffleDeck()" method.
What I am trying to do is create a method that will take an array parameter (which will be the deck of cards) shuffle the cards, and return the shuffled array list.
This is the code:
class Card
{
int value;
String suit;
String name;
public String toString()
{
return (name + " of " + suit);
}
}
public class PickACard
{
public static void main( String[] args)
{
Card[] deck = buildDeck();
// display Deck(deck);
int chosen = (int)(Math.random()* deck.length);
Card picked = deck[chosen];
System.out.println("You picked a " + picked + " out of the deck.");
System.out.println("In Blackjack your card is worth " + picked.value + " points.");
}
public static Card[] buildDeck()
{
String[] suits = {"clubs", "diamonds", "hearts", "spades" };
String[] names = {"ZERO", "ONE", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "Jack", "Queen", "King", "Ace" };
int i = 0;
Card[] deck = new Card[52];
for ( String s: suits )
{
for ( int v = 2; v<=14; v++)
{
Card c = new Card();
c.suit = s;
c.name = names[v];
if ( v == 14)
c.value = 11;
else if ( v>10)
c.value = 10;
else
c.value = v;
deck[i] = c;
i++;
}
}
return deck;
}
public static String[] shuffleDeck( Card[] deck)
{
/** I have attempted to get two index numbers, and swap them.
I tried to figure out how to loop this so it kind of simulates "shuffling".
*/
}
public static void displayDeck( Card[] deck)
{
for ( Card c: deck)
{
System.out.println(c.value + "\t" + c);
}
}
}
解决方案
How about:
List<Card> list = Arrays.asList(deck);
Collections.shuffle(list);
Or one-liner:
Collections.shuffle(Arrays.asList(dec));
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