本文介绍了反转数组中的内容的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一组要反转的数字.我相信我的代码中的函数是正确的,但我无法获得正确的输出.
I have an array of numbers that I am trying to reverse. I believe the function in my code is correct, but I cannot get the proper output.
输出为:10 9 8 7 6.为什么我不能得到另一半的数字?当我从计数中删除/2"时,输出显示为:10 9 8 7 6 6 7 8 9 10
The output reads: 10 9 8 7 6.Why can't I get the other half of the numbers? When I remove the "/2" from count, the output reads: 10 9 8 7 6 6 7 8 9 10
void reverse(int [], int);
int main ()
{
const int SIZE = 10;
int arr [SIZE] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
reverse(arr, SIZE);
return 0;
}
void reverse(int arr[], int count)
{
int temp;
for (int i = 0; i < count/2; ++i)
{
arr[i] = temp;
temp = arr[count-i-1];
arr[count-i-1] = arr[i];
arr[i] = temp;
cout << temp << " ";
}
}
推荐答案
这就是我的方法:
#include <algorithm>
#include <iterator>
int main()
{
const int SIZE = 10;
int arr [SIZE] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
std::reverse(std::begin(arr), std::end(arr));
...
}
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