本文介绍了UnicodeDecodeError : 'ascii' 编解码器无法解码位置 0 中的字节 0xe0:序号不在范围内 (128)的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

在我的一台机器上,当我使用 google 应用程序引擎或 django 时出现错误.

On one of my machines I have the error when I am working with google apps engine or django.

例如:

  • app.yaml

  • app.yaml

application: demas1252c
version: 1
runtime: python
api_version: 1


handlers:
   - url: /images
static_dir: images
   - url: /css
static_dir: css
   - url: /js
static_dir: js
   - url: /.*
script: demas1252c.py

  • demas1252c.py

  • demas1252c.py

    import cgi
    import wsgiref.handlers
    
    
    from google.appengine.ext.webapp import template
    from google.appengine.ext import webapp
    
    
    class MainPage(webapp.RequestHandler):
    def get(self):
    values = {'id' : 10}
    
    
    self.response.out.write(template.render('foto.html', values))
    
    
    application = webapp.WSGIApplication([('/', MainPage)], debug = True)
    wsgiref.handlers.CGIHandler().run(application)
    

  • foto.html

  • foto.html

    <!DOCTYPE html>
    <html lang="en">
        <head></head>
    <body>some</body>
    </html>
    

  • 错误信息:

    C:artefactsdevproject>"c:Program FilesGooglegoogle_appenginedev_appserver.py" foto-hosting
    Traceback (most recent call last):
      File "c:Program FilesGooglegoogle_appenginedev_appserver.py", line 69, in <module>
        run_file(__file__, globals())
      File "c:Program FilesGooglegoogle_appenginedev_appserver.py", line 65, in run_file
        execfile(script_path, globals_)
      File "c:Program FilesGooglegoogle_appenginegoogleappengine	oolsdev_appserver_main.py", line 92, in <module>
        from google.appengine.tools import dev_appserver
      File "c:Program FilesGooglegoogle_appenginegoogleappengine	oolsdev_appserver.py", line 140, in <module>
        mimetypes.add_type(mime_type, '.' + ext)
      File "C:Python27libmimetypes.py", line 344, in add_type
        init()
      File "C:Python27libmimetypes.py", line 355, in init
        db.read_windows_registry()
      File "C:Python27libmimetypes.py", line 260, in read_windows_registry
        for ctype in enum_types(mimedb):
      File "C:Python27libmimetypes.py", line 250, in enum_types
        ctype = ctype.encode(default_encoding) # omit in 3.x!
    UnicodeDecodeError: 'ascii' codec can't decode byte 0xe0 in position 0: ordinal not in range(128)
    

    当我在 django 中处理静态文件(没有 gae)时,我有非常相似的错误(有不同的堆栈).

    When I am working with static files in django (without gae) I have very similar error (with different stack).

    我试图找到错误的原因并在mimetypes.py中添加了代码:

    I tried to find the reason of error and added code to mimetypes.py:

    print '====='
    print ctype
    ctype = ctype.encode(default_encoding) # omit in 3.x!
    

    然后我在控制台中收到下一条消息:

    Then I get next messages in my console:

    =====
    video/x-ms-wvx
    =====
    video/x-msvideo
    =====
    рєфшю/AMR
    Traceback (most recent call last):
    

    在注册表 HKCR/Mime/Database/ContentType/我有五个带有俄文(西里尔文)字母的键.但是我该如何解决这个错误?

    In the registry HKCR/Mime/Database/ContentType/ I have five keys with russian (cyrilic) letters. But how can I fix this error?

    推荐答案

    这是 mimetypes 中的一个错误,由注册表中的错误数据触发.(рєфшю/AMR 根本不是有效的 MIME 媒体类型.)

    This is a bug in mimetypes, triggered by bad data in the registry. (рєфшю/AMR is not at all a valid MIME media type.)

    ctype_winreg.EnumKey 返回的注册表项名称,mimetypes 期望它是一个 Unicode 字符串,但它不是'吨.与 _winreg.QueryValueEx 不同,EnumKey 返回一个字节字符串(直接来自 Windows API 的 ANSI 版本;_winreg 在 Python 2 中不使用Unicode 接口,即使它返回 Unicode 字符串,所以它永远不会正确读取非 ANSI 字符).

    ctype is a registry key name returned by _winreg.EnumKey, which mimetypes is expecting to be a Unicode string, but it isn't. Unlike _winreg.QueryValueEx, EnumKey returns a byte string (direct from the ANSI version of the Windows API; _winreg in Python 2 doesn't use the Unicode interfaces even though it returns Unicode strings, so it'll never read non-ANSI characters correctly).

    因此,尝试 .encode 失败,出现 UnicodeDecode Error 在将其编码回 ASCII 之前尝试获取 Unicode 字符串!

    So the attempt to .encode it fails with a Unicode​Decode​Error trying to get a Unicode string before encoding it back to ASCII!

    try:
        ctype = ctype.encode(default_encoding) # omit in 3.x!
    except UnicodeEncodeError:
        pass
    

    mimetypes 中的这些行应该简单地删除.

    These lines in mimetypes should simply be removed.

    预计到达时间:添加到错误跟踪器.

    这篇关于UnicodeDecodeError : 'ascii' 编解码器无法解码位置 0 中的字节 0xe0:序号不在范围内 (128)的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

    08-20 04:47
    查看更多